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#976 Help Me ! » Find Equation for the Ferris Wheel » 2024-03-02 02:43:54

mathxyz
Replies: 4

In 2008, the Singapore Flyer opened up as the world's largest Ferris wheel. It has a maximum height of 165 meters and a diameter of 150 meters, with one full rotation taking about 30 minutes. Find an equation for the wheel if the center of the wheel is on the y-axis also known as the x = 0 line.

Let's see what I can do here.


If x = o, then the center is (0, y) = (h, k).


The height of the wheel is 165 meters which is the diameter.


I say the value of y is halfway up the wheel.


So, y = 165/2 = 82.5 meters.


This leads to the center point being (0, 82.5).


The radius is r.


r = (1/2)(150) = 75 meters.


I now have the radius and center point.


I think the next step is to plug this information into the standard form of an equation of a circle:


(x - h)^2 + (y - k)^2 = r^2


Is this correct so far?

#977 Help Me ! » Convert Standard Form to General Form » 2024-03-02 02:17:04

mathxyz
Replies: 12

Convert each equation in standard form to general form.


The general form of the equation of a circle is given sat?


x^2 + y^2 + ax + by + c = 0.


1. (x - 3)^2 + (y + 3)^2 = 9


2. (x + 1)^2 + (y - 2)^2 = 4


Question 1


(x - 3)^2 + (y + 3)^2 = 9


(x - 3)(x - 3) + (y + 3)(y + 3) = 9


x^2 - 6x + 9 + y^2 + 6y + 9 - 9 = 0


x^2 + y^2 - 6x + 6y + 18 - 9 = 0


x^2 + y^2 - 6x + 6y + 9 = 0


You say?


Question 2


(x + 1)^2 + (y - 2)^2 = 4


(x + 1)(x + 1) + (y - 2)(y - 2) = 4


x^2 + 2x + 1 + y^2 -4y + 4 - 4 = 0


x^2 + y^2 + 2x - 4y + 1 + 4 - 4 = 0


x^2 + y^2 + 2x - 4y + 5 - 4 = 0


x^2 + y^2 + 2x - 4y + 1 = 0


You say?

#978 Help Me ! » Standard Form of Equation of the Circle...Part Three » 2024-03-01 11:20:10

mathxyz
Replies: 6

Find the standard form of the equation of the circle with endpoints of a diameter at (4, 3) and (0, 1).

I think the midpoint must be found here.


If that's the case, let M = midpoint.


M = (2, 2)


I now need r.


Let r = the distance from any of the endpoints of the circle to the midpoint.


I will use the endpoint (0, 1).


r = sqrt{(0 - 2)^2 + (1 - 2)^2}


r = sqrt{5}


Plug r into x^2 + y^2 = r^2.


x^2 + y^2 = (sqrt{5})^2


My answer is x^2 + y^2 = 5.


Yes?

#979 Re: Help Me ! » Find Factors » 2024-03-01 11:10:36

KerimF wrote:
amnkb wrote:

All the factors are:
1, 2, 3, 4, 6, 12, 1x, 2x, 3x, 4x, 6x, 12x, 1x^2, 2x^2, 3x^2, 4x^2, 6x^2, 12x^2

If I understood well the exercise, amnkb gave the right answer.

For example. let us assume x=5
12x^2 = 300
So, its factors are:
1, 2, 3, 4, 6, 12, 5, 10, 15, 20, 30, 60, 25, 50, 75, 100, 150, 300
-----------------   -----------------------   -----------------------------

Ok. Sounds good. Thanks for your input.

#980 Help Me ! » Standard Form of Equation of the Circle...Again » 2024-03-01 11:09:16

mathxyz
Replies: 6

Find the standard form of the equation of the circle with center (-3, 1) and tangent to the y-axis.


Let me see.


If the circle is tangent to the y-axis, then it must touch the line x = 0 at the point (0, 1).


I need to find r.


r = sqrt{(0 - (-3))^2 + (1 - 1)^2}


r = 3


x^2 + y^2 = r^2


x^2 + y^2 = (3)^2


The equation is x^2 + y^2 = 9.


You say?

#981 Help Me ! » Standard Form of Equation of the Circle » 2024-03-01 10:59:06

mathxyz
Replies: 8

Find the standard form of the equation of the circle centered at the origin and containing the point (-2, 3).


Let's do this one.


The standard form is x^2 + y^2 = r^2.


I need to find r.


r = sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}


r = sqrt{(-2 - 0)^2 + (3 - 0)^2}


r = sqrt{(-2)^2 + (3)^2}


r = sqrt{4 + 9}


r = sqrt{13}


Plug sqrt{13} into x^2 + y^2 = r^2 for r.


x^2 + y^2 = (sqrt{13})^2


x^2 + y^2 = 13


Yes?

#982 Re: Help Me ! » Equation of the Circle...Again » 2024-03-01 10:43:59

amnkb wrote:
FelizNYC wrote:

TWO LOVES

1. MATHEMATICS

2. CLASSICAL GUITAR HYMNS

Hi, solo_guitar!
big_smile

What? Who cares? Stick to question at hand.

#983 Re: Help Me ! » Find GCF » 2024-03-01 10:42:57

amnkb wrote:
FelizNYC wrote:

Find the GCF of 45 and 75.

Another way is to do the prime factorization w/ a table:

factors
 45: 3 * 3 * 5
 75: 3     * 5 * 5
---+--------------
GCF: 3     * 5    = 15

The prime factorization method is cool.

#984 Re: Help Me ! » Find Factors » 2024-03-01 10:41:22

amnkb wrote:
FelizNYC wrote:

You know, the AI Questions app tells me that the factors are 1, 2, 3, 4, 6, x, 2x, 4x, 6x. I also know that my work is correct. Who's right?

you did the factoring right
But you didn't put things back together in *all* the possible ways
AI is many times stupid at math
But it is right-er this time
All the factors are:
1, 2, 3, 4, 6, 12, 1x, 2x, 3x, 4x, 6x, 12x, 1x^2, 2x^2, 3x^2, 4x^2, 6x^2, 12x^2

I checked with professor Leonard. He said my answer is correct.

#985 Re: Help Me ! » Equation of the Circle...Again » 2024-02-29 09:15:26

Bob wrote:

x^2 - 2x + 1 + y^2 + 4y + 4 - 9 = 0


x^2 + y^2 - 2x + 4y + 1 + 5 - 9 = 0

The plus 4 on the correct line has become plus 5 on the next line.

Bob

Thank you. Someone else pointed out my typo. Rest assure that this is simply a self-study of math learned back in the 80s and 90s. What else is a middle-aged lonely guy to do?

TWO LOVES

1. MATHEMATICS

2. CLASSICAL GUITAR HYMNS

#986 Re: Help Me ! » Equation of the Circle...Again » 2024-02-29 09:13:33

KerimF wrote:
FelizNYC wrote:

x^2 - 2x + 1 + y^2 + 4y + 4 - 9 = 0
x^2 + y^2 - 2x + 4y + 1 + 5 - 9 = 0

x^2 - 2x + 1 + y^2 + 4y + 4 - 9 = 0
to
x^2 + y^2 - 2x + 4y + 1 + 5 - 9 = 0

It is actually:
x^2 + y^2 - 2x + 4y + 1 + 4 - 9 = 0

Your typo was 5 instead of 4.
I recall how, me too, I did this type of mistake in some math exams (when I was a student many decades ago). I even failed in one of them because of a silly typo I did.

I got it. Thanks. It was simply a typo.

#987 Re: Help Me ! » Equation of the Circle...Again » 2024-02-28 17:13:59

KerimF wrote:
FelizNYC wrote:

(x - 1)^2 + (y + 2)^2 = 9
...
x^2 + y^2 - 2x + 4y - 3 = 0

(x - 1)^2 + (y + 2)^2 = 9

Let us assume x=1:
(1 - 1)^2 + (y + 2)^2 = 9
(y + 2)^2 = 9
y + 2 = 3
y = 3 - 2
y = 1

Now,
x^2 + y^2 - 2x + 4y - 3 = 0

Let us verify if this final form is also satisfied for x=1 and y=1
1^2 + 1^2 - 2*1 + 4*1 - 3 = 0
1 + 1 - 2 + 4 - 3 = 1 ≠ 0

I am afraid that you did a typo somewhere.


Can you show me where the error was made?

#988 Help Me ! » Equation of the Circle...Again » 2024-02-28 09:10:35

mathxyz
Replies: 14

The standard form of an equation of the circle of radius r and center at the origin (0, 0) is x^2 + y^2 = r^2.


The general form of an equation of a circle is given by
x^2 + y^2 + ax + by + c = 0.


The standard form of an equation of a circle with radius r and center
(h, k) is given by (x - h)^2 + (y - k)^2 = r^2.


Write the standard form and the general form of the equation of each circle of radius r and center (h, k) .


r = 3; (h, k) = (1, -2)


Let me see.


This circle is not centered at the origin.


Plug r = 3, h = 1, and k = -2 into


(x - h)^2 + (y - k)^2 = r^2


(x - 1)^2 + (y - (-2))^2 = 3^2


(x - 1)^2 + (y + 2)^2 = 9....This is the standard form not centered at the origin.


Next, write the general form of the equation of the circle.


(x - 1)^2 + (y + 2)^2 = 9


(x - 1)(x - 1) + (y + 2)(y + 2) - 9 = 0


x^2 - 2x + 1 + y^2 + 4y + 4 - 9 = 0


x^2 + y^2 - 2x + 4y + 1 + 5 - 9 = 0


x^2 + y^2 - 2x + 4y - 3 = 0


You say?

#989 Re: Help Me ! » Equation of the Circle » 2024-02-28 03:51:19

KerimF wrote:
FelizNYC wrote:

In that case, the equation should be

x^2 + y^2 + 10x + 4y - 20 = 0

Yes?

Yes.

Perfect. I will post similar questions when time allows.

#990 Re: Help Me ! » Inverse Functions. Why rewrite as y=f(x) » 2024-02-27 17:11:15

paulb203 wrote:

What does this mean? And does it have to be y?

By rewriting, for example, f(x)=2x+3, as y=2x+3, are we simply stating that something = 2x+3; and in the first case we’re calling that something f(x), and in the second case we’re calling it y?

Does the y have anything to do with the y axis in x,y coordinates? Or is just a randomly chosen letter? Could it just as well be z, or a, or b, etc?

Note: y and f(x) mean the same thing. It's like saying car and automobile.

For example, y = 2x + 5 can also be written as f(x) = 2x + 5. In terms of functions, f(x) is mostly used.

#991 Re: Help Me ! » Equation of the Circle » 2024-02-27 16:03:25

Bob wrote:

Q1 Perfect.

Q2. Almost. Correct up to this line:

x^2 + 10x + 25 + y^2 + 4y + 4 = 49

You've brought the 49 across to the left hand side but forgotten there's already +25 and + 4 there.

Bob

In that case, the equation should be

x^2 + y^2 + 10x + 4y - 20 = 0

Yes?

#992 Re: Help Me ! » Equation of the Circle » 2024-02-27 15:58:36

KerimF wrote:

The general form of Q1 is:
x^2 + y^2 - 9 = 0

Cool. Thanks.

#993 Re: Help Me ! » List the Factors of 3x^3 » 2024-02-27 15:57:17

Bob wrote:

Maybe the problem here is that the word factor is being used to mean two similar but different things.

If N is a whole number then another whole number m is a factor if N/m is a whole number.

eg. 8 is a factor of 48 because 48/8 = 6

But if an algebraic expression (E) can be split into two expressions (F and G) that multiply to make E then F and G are said to be factors.

eg. 

x and (x+2) are factors of E. 

If only numbers are involved then the GCF is clear,

eg The GCF of 45 and 75 is 15

In pure mathematical terms saying that the GCF of 12x^2 and 28x^4 is 4x^2 is a questionable use of GCF because we don't even know if x is a whole number so how can we ask questions about the greatest factor.

But the Prof. goes on to use his earlier method to factorise (second definition) algebraic expressions. Nothing wrong with that; methods that work but have use dubious logic do exist in maths . I teach integration by saying have a guess based on what you know about differentiation; check if it works; and modify your guess if it doesn't.

Bob


The idea of GCF is basic. I don't think professor Leonard wants to go too deep mathematically in a course called Intermediate Algebra. Students in such a course are beginning algebra students.

#994 Help Me ! » Equation of the Circle » 2024-02-27 04:21:34

mathxyz
Replies: 14

The standard form of an equation of the circle of radius r and center at the origin (0, 0) is x^2 + y^2 = r^2.


The general form of an equation of a circle is given by
x^2 + y^2 + ax + by + c = 0.


The standard form of an equation of a circle with radius r and center
(h, k) is given by (x - h)^2 + (y - k)^2 = r^2.


Write the standard form and the general form of the equation of each circle of radius r and center (h, k) .


1. r = 3; (h, k) = (0, 0)


2. r = 7; (h, k) = (-5, -2)


Question 1



This circle is centered at the origin.



x^2 + y^2 = r^2



Let r = 3.



x^2 + y^2 = (3)^2



x^2 + y^2 = 9===>standard form



How do I write x^2 + y^2 = 9 in the general form
x^2 + y^2 + ax + by + c = 0?


Question 2


r = 7; (h, k) = (-5, -2)


This circle is not centered at the origin.


(x - h)^2 + (y - k)^2 = r^2


(x - (-5))^2 + (y - (-2))^2 = (7)^2


(x + 5)^2 + (y + 2))^2 = 49


(x + 5)(x + 5) + (y + 2)(y + 2) = 49


x^2 + 10x + 25 + y^2 + 4y + 4 = 49


I need to write  it in the form x^2 + y^2 + ax + by + c = 0.


My answer is: x^2 + y^2 + 10x + 4y - 49 = 0.


You say?

#995 Re: Help Me ! » List the Factors of 3x^3 » 2024-02-27 03:47:49

Bob wrote:

Watched it. Great vid!

But I didn't hear him say what he means by 'evenly divided'.  It's not a maths expression that I'm familiar with.

Did it come from a text book question?

Bob

Evenly divided are my words to mean there is no remainder.

For example: 3x^2 ÷ x = 3x because 3x times x = 3x^2.

Given 3x^2 and 3x, find the GCF.

The GCF IS 3x. Why?

I say 3x is the GCF because 3x^2 can be evenly divided (no remainder) by 3x.

We can divide 3x^2 by 3x but the other way around.

#996 Re: Help Me ! » List All Common Factors » 2024-02-27 03:41:47

Bob wrote:

OK, thanks for the link.  I really like this guy's teaching style; it must be great to be in his class.

He is trying to find common factors so it is sufficient to find x, x^2, x^3 etc and not bother about 3x, 3x^2 and 3x^3.

He takes care of the number factors separately so it works.

So it all depends on what the question asks for.

If it just wants the factors then 3x etc should be in the list, but if you're after the GCF you can leave them out.

Bob

I agree. Professor Leonard is an amazing teacher. He wants students to understand math and not just to know enough to pass the test or the class.

#997 Re: Help Me ! » Factoring & Relatively Prime » 2024-02-27 03:39:17

Bob wrote:

Relatively prime means the two (or more) numbers have only 1 as a common factor.

For example: 6(= 2 x 3) and 11 are relatively prime, 45( = 3 x 3 x 5) and 77( = 7 x 11) are relatively prime

6 and 15 are not;  as 3 is also a factor of both.

If you factorise out the GCF from an expression then the numbers left must have no common factor because if there was another factor for both then you haven't found the greatest common factor.

So the numbers left are relatively prime.

I'll make up another example.

42x + 70 = 2(21x + 35)  21 and 35 are not relatively prime, but I haven't yet factored out all the common factors.

Let's do that:

42x + 70 = 2(21x + 35) = 14(3x + 5)  Now we have 3 and 5, and these are relatively prime.

Bob


Thanks. Easy to understand now.

#998 Help Me ! » Factoring & Relatively Prime » 2024-02-26 04:42:50

mathxyz
Replies: 2

Factor 49x - 35.


This is what professor Leonard did:


Divide each term by the GCF.


The GCF is 7.


49x ÷ 7 = 7x


-35 ÷ 7 = -5


7(7x - 5)....done!


However, he went on to say that the binomial inside the parentheses is called RELATIVELY PRIME. Leonard stated that the binomial inside the parentheses will always be relatively prime.

What does he mean by those words?

#999 Re: Help Me ! » Find GCF Involving Variables » 2024-02-26 03:28:19

Bob wrote:

Correct.

Bob

Like Richie Cunningham is famous for saying the line on Happy Days:
"I'm cooking with gas."

#1000 Re: Help Me ! » GCF Involving Variables » 2024-02-26 03:26:57

Bob wrote:

Yes for both.

Bob

It certainly feels good to know that I am right this time around. Math helps keep my brain cells alive. No pun intended.

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