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am spouse to cancel the 20 next to the y right ? so its not a negative 20
nop am subtracting 20 from both sides its asking for the point slope y-k=m(x-H)
17- y-k=m(x-h)
y-20=-31\14X- -62031\14
-20 -20
Y=-31/14x- -62311/14
y-20=-31/14x-62031\14
y-20=-31/14*2011-62031/14
y-20=-62031\14-62031/14
y-20=0
-20 -20
Y=-20
18. During which year was there 10 computers per student?
18- y= (-31/14)x+62311/14
Y = (-31/14)10+62311/14
Y=-155\7+62311\14
Y=-310\14+62311\14
Y=62001\14
hhhh i didnt mean do do the sad face there spouse to be parentheses and yeah horrible numbers ![]()
and for the point slope form this is whaT i got
y-k=m(x-h)
y-20=-31/14(x-2001)
y-20=-31/14x-62031\14
16-m=(y2-y1)\(x2\x1)
(4.5-20)\(2008-2001)=
(9/2-40/2)\7=
(-31\2)\7= -31\14
Slope intercept
Y=(-31/14)x+b
20=(-31\14)(2,001)+b
B=20+62031/14=280\14+
62,031/14=62,311/14
Y=(-31/14)x+62311/14
did i start correct?like the beginning
for number 16 this is what i got i was wondering if it was correct
y=mx+b
so the 4.5= 9/2
9/2-20/2008-2001= -31\2 over 7 =-31\14 so thats my slope
2001=(-31\14(20)+b
2001= -310\7+B
14317\7=b
y=-310/7X+14317/7
for number 15 are the ordered pairs (2001,20) (2008,4.5)
ok thanx alot ![]()
in 13 its asking for the point slope so really 115=8(1)+b
115=8+b
b=123
y=-8X+123
is solving for 12 am spouse to do 13 in this equation y-k=m(x-h)
y-115=-8(x-1)
y-115=-8x--8
y-115=-8x+8
-115 -115
y=-8x+-107
is that correct?
115=8(1)+b
115=8+b
b=123
y=-8X+123
y=mx+b
32\-4= -8
isint the slope 8 ? because 32/4=8
y-83=8(x-5)
y=mx+b
y=8x+b
83=8(5)+b
83=40+b
83-40=b
43=b
y=8X+43
y=-32x+147
nop can u give me an equation
ok so what about 14 its confusing
is 8
y-y1\x-x1
y-115=(-8)(x-1)
y-115=-8x-8
y=-8X- -107
y=-8x+107