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Can you list some though? I just want a couple of the infinite solutions.
This (I think) is an elliptical curve, so there should be an infinite number of solutions.
Oh, right. I am looking for integer solutions.
Yeah, I understand how to do the problem. The fruit salad question was easy. Just add up and divide by the 2 quarts you have to get 3/8.
I wound up with this Diophantine equation to solve:
And I would really like to know the solutions
. I would prefer that you list all of the possible answers, because I'm trying out an equation and the more solutions, the better.J.R.R Tolkien, author of The Hobbit, stated in 1970 that on one of his birthdays the age he turned was the square root of the year. What year was he born in?
For the first problem, I'm compelled to just add up the numbers, but that doesn't seem right... And for the second one, I just don't know where to begin.
What is the trick? Is it an algebraic trick that anyone can use without the use of a computer, or is it a trick in Mathematica?
Oh... But do you know what are the two Quartics? Wolfram Alpha isn't capable of understanding my input, for some weird reason. Really wish I had Mathematica.
Sorry that I've been posting a lot of problems lately...
I need to find in the functionI'm trying to factor the octic
into two Quartics. (It should be factorable by the way!)Yeah sure. That would help a lot.
Wow, complicated! Okay, thanks!
Who's the Mighty M? Sorry, but I haven't been on the Math is Fun Forum in a while.
Yes, you will always know for .Oh... That is an error on my part. It should say
... Sorry!Yes, no matter what, it will be in that form.
I just think that it would be easier to have a function that you substitute the knowns into and get the unknowns...
Because right now, it takes a long time to find all the unknowns with the standard method, but substituting everything into a function, you can find one unknown in and find the others really quickly.
Sorry, I still do not understand what you meant by "I meant that 2 over the 1"
It's okay if there isn't a function that can represent this system. I was just wondering. It would make my calculations much easier in the future.
A zero.
Do you have any pointers on how to tackle this kind of system of equations? I want to try the same method, but generalize it. Perhaps that could help.
I gave an example...
What I meant, is that using a polynomial, can we solve for the unknown values? (by the way, ) are already known.For the example, you start off with knowing so you can find and the cubic. Once you solve the cubic (for ), you can find by substituting the knowns into . Giving you . Using that, you can find and finish the system.I've been trying for some time, but I don't have the resources such as Mathematica and I don't know if Wolfram Alpha even knows how to do this command.
I find it amazing how the roots of this polynomial can be expressed with cosines. Is there a mathematical way that can solve this?
I feel like my follow through is already simple enough. You simply use All Roots of Unity to solve the problem...
Okay, that works too!
Full work:
Let . From that, we have which simplifies into .Setting
and we get . Equating terms together, we get and . Since , we have . So for .We want the real part so we use the formula
to get the roots...
I substituted
to getWe want the roots, so setting
will give us the roots.