Math Is Fun Forum

(80/2000000 x 100)%

Thank you

I'm definitely going with Cambridge as my firm. As for my insurance.....

(still to hear from Bristol, but I'm expecting an offer)

Erm, rather unexpectedly, I received a letter this morning offering me a place to read Mathematics at Trinity College, Cambridge.

The conditions of the offer are pretty tough, though.

I'm absolutely over the moon

Jane, would you mind providing another hint to this?

Well the first part comes out from the sum of a geometric series:

Induction proves the second pretty quickly:

Obviously the first part could also be done (and more quickly) by induction, but I feel induction gets rid of the 'why' behind it. I'm sure you're going to show me a nicer way to do the second part

I received an offer from the University of Warwick the other day. They want AABb (I already have one A though) and either a 2 in STEP or a merit in AEA.

Yep, just bothered to actually think about this.

Thanks.

Although, I seem to get that the x component of the acceleration is -gsinθ?

Don't worry, I got it.

Ahh, thanks for sharing that

Also, "if three numbers are in arithmetic progression whose common difference is not a multiple of 3, at least one of them is divisible by 3" is pretty much what I stated in post #3

Maybe the reason I can't prove it is because it's not true.

4, 7, 10.

You're right.

I'm actually rather stupid.

The factor should be (x+1), in which case x = -1 does work, as we can let x = cosθ (which we have to do anyway). Also,

Thanks

The point of the question was obviously to work in the trigonometric form, as the value of phi s.t