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We can substittue (5) in (4),and we'll get:
Now from
Now if we su8bstittue all these values in (3),we will get:
Now if we collect the terms we'll get:
Now from the formula in the beginning,
we see that we have just ,soNow the solution is
Sorry,I'm trying to write you the answer but it doesn't work
But you can try values from 0.000000001 to 9.99999,or to do this:
I think that x must be
because x msut be postive,and the side of the rectangle can't be 0 or negative soThere are many ways to evaluate this kind of calcul:
1.First multiply 4X8,than 4X6,4X6 and 4X2
and then get one column under the numbers you wrote,and start again with the 6 but just one place into the left.
And then just do the sum of the two columns
2.Here is another example
If you want to evaluate this calcul do like this:
2668X100=266800
2668X10=26680 now 26680X3=80040
2668X3X2=8004X2=16008
and than do the substraction of all the results you had,do like this: 266800-80040-16008=170752 and this is the result of multiplying 2668 by 64!!!!!!!
Do you understand how to do it????
Here is the solution for the Area:
First let us split the "figure"into to figures.
The first (A1) is the triangle and the second(A2) the rectangle.
Now we'll work first with A1(A=area)
We had that BC=x/squareroot(2)
CF=x
From Pithgora's theorem we have:
BF^2=x^2-(x/squareroot(2))^2
BF^2=x^2-x^2/2
BF^2=x^2/2
BF=x/squareroot(2)
The area of the triangle FBC is A1=(BF*BC)/2
A1=(x/squareroot(2)*x/squareroot(2))/2
A1=(x^2/2)/2
A1=x^2/4
Now the area of the rectAngle is :
A2=FE*DE
A2=(10-x)x
A2=10x-x^2
Now the total area is:
A=A2+A1
A=10x-x^2+x^2/4
A=10x-(x^2-x^2/4)
A=10x-((4x^2-x^2)/4)
A=10x-(3x^2/4)
And this is the solution
Here is the solution about the BC=x/2^(1/2)
From B make a line down from b to the segment CF,and the point that touch CF name it A.
CF=DE=x so CA=1/2*x
From C make a vertical line,and from B a horizontal line,and the point that begins to both of segments name it H,and you 'll have a square (HBCA).
Now:
CA=BA=x/2
BC^2=CA^2+BA^2
BC^2=x^2/4+x^2/4
BC^2=2x^2/4
BC^2=x^2/2
BC=squarerrot(x^2/2)
BC=x/squareroot(2)
You can multiply numbers with 9 using your fingers.
Example.
9X3=27
Now look your 10 fingers,and when you multiply 9 by a number,the number wich is used to multiply 9 is your finger (starting from the left to the right) that you should "hide",so 9X3=27,and if you "hide" your third finger you will se that in the beginning you have 2 finers,and after the "hiden" finer you'll have seven fingers,so it makes 27!!!!!!!
Another example:
9X7=63
"Hide" your 7-th finger(the seventh beginning from the left to the right) and you'll have,6 fingers in the beginning and 3 fingers at the end!!!!!!!!!!
Hi every body,I am Gramoz from Kosovo,and I decided to join this forum because it looked very interesting.