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#126 Re: Help Me ! » This has been bugging me... » 2008-10-05 23:36:53

  (1)
from here we see that
     (2)
Now if we multiply all the terms in the brackets,will have
  (3)
From (1),we can notice that we dont have just x alone,without exponent,so it means that in the equation all terms that have x should be "elminated",so:
          (4)
Now we use the same methode with

                   (5)

We can substittue (5) in (4),and we'll get:

            (6)


Now from

Now if we su8bstittue all these values in (3),we will get:

Now if we collect the terms we'll get:

Now from the formula in the beginning,

we see that we have just 
,so

Now the solution is 

#127 Re: Help Me ! » combinatorial proof » 2008-10-04 10:09:30

Sorry,I'm trying to write you the answer but it doesn't work

#133 Re: Help Me ! » need help with a few problems » 2008-08-31 21:33:27

But you can try values from 0.000000001  to  9.99999,or to do this:

and the result of this limit is 25.
So x->10,or x=9.9999999999999999999...
I'm not sure if this is the correct solution because I didn't learn yet this kind of examples,but you can ask also someone else if you want.
Did you understand how to procede to get the result of the question 3??????
:D

#134 Re: Help Me ! » need help with a few problems » 2008-08-31 21:25:07

I think that x must be

because x msut be postive,and the side of the rectangle can't be 0 or negative so

#135 Re: Help Me ! » Help » 2008-08-31 06:07:11

There are many ways to evaluate this kind of calcul:
1.First   multiply 4X8,than 4X6,4X6 and 4X2
and then get one column under the numbers you wrote,and start again with the 6 but just one place into the left.
And then just do the sum of the two columns
2.Here is another example
If you want to evaluate this calcul do like this:
2668X100=266800
2668X10=26680 now 26680X3=80040
2668X3X2=8004X2=16008

and than do the substraction of all the results you had,do like this: 266800-80040-16008=170752 and this is the result of multiplying 2668 by 64!!!!!!!
Do you understand how to do it????

#140 Re: Help Me ! » need help with a few problems » 2008-08-31 00:27:36

Here is the solution for the Area:

First let us split the "figure"into to figures.
The first (A1) is the triangle and the second(A2) the rectangle.

Now we'll work first with A1(A=area)

We had that BC=x/squareroot(2)
CF=x
From Pithgora's theorem we have:

BF^2=x^2-(x/squareroot(2))^2
BF^2=x^2-x^2/2
BF^2=x^2/2

BF=x/squareroot(2)

The area of the triangle FBC is A1=(BF*BC)/2
A1=(x/squareroot(2)*x/squareroot(2))/2
A1=(x^2/2)/2

A1=x^2/4

Now the area of the rectAngle is :
A2=FE*DE
A2=(10-x)x

A2=10x-x^2

Now the total area is:
A=A2+A1
A=10x-x^2+x^2/4
A=10x-(x^2-x^2/4)
A=10x-((4x^2-x^2)/4)

A=10x-(3x^2/4)
And this is the solution big_smile

#141 Re: Help Me ! » need help with a few problems » 2008-08-31 00:13:34

Here is the solution about the BC=x/2^(1/2)

From B make a line down from b to the segment CF,and the point that touch CF name it A.
CF=DE=x so CA=1/2*x

From C make a vertical line,and from B a horizontal line,and the point that begins to both of segments name it H,and you 'll have a square (HBCA).
Now:
CA=BA=x/2
BC^2=CA^2+BA^2
BC^2=x^2/4+x^2/4
BC^2=2x^2/4
BC^2=x^2/2
BC=squarerrot(x^2/2)
BC=x/squareroot(2)

#142 This is Cool » Multiplying with fingers!!!!!! » 2008-08-30 23:31:37

G_Einstein
Replies: 4

You can multiply numbers with 9 using your fingers.
Example.
9X3=27
Now look your 10 fingers,and when you multiply 9 by a number,the number wich is used to multiply 9 is your finger (starting from the left to the right) that you should "hide",so 9X3=27,and if you "hide" your third finger you will se that in the beginning you have 2 finers,and after the "hiden" finer you'll have seven fingers,so it makes 27!!!!!!!

Another example:
9X7=63
"Hide" your 7-th finger(the seventh beginning from the left to the right) and you'll have,6 fingers in the beginning and 3 fingers at the end!!!!!!!!!!
big_smile

#143 Introductions » Hi everybody » 2008-08-30 23:16:23

G_Einstein
Replies: 4

Hi every body,I am Gramoz from Kosovo,and I decided to join this forum because it looked very interesting.

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