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#126 Re: Help Me ! » Follow-up on my last post » 2012-06-27 03:06:31

(x1, y1) then it would be (1, 1).

#127 Re: Help Me ! » Follow-up on my last post » 2012-06-27 03:01:45

I understand what the slope is and what the points are for a point-slope problem for example:

y-4= -3(x-2)
The slope of the equation is -3
The point from this equation is (2, 4)

And the same in slope-intercept.

And I understand how to get the slope-point form from two points. But 1,115.00 and 5,83.00 aren't my points, they're coordinates, right? And I don't know how you draw points from coordinates..

#129 Re: Help Me ! » Follow-up on my last post » 2012-06-27 02:49:30

What do you mean "these are the points"? Isn't 1,115 just one point?

#130 Re: Help Me ! » Follow-up on my last post » 2012-06-27 02:44:58

Yes.
What about y - 8920 = 8(x - 1,115) ?

#131 Re: Help Me ! » Follow-up on my last post » 2012-06-27 02:39:34

I'm not sure if the answer is y - 123 = 8 (x - 1) but that's what I got.

#132 Re: Help Me ! » Follow-up on my last post » 2012-06-27 02:18:34

So instead of 0 I could pick 1,115.00 and then do the same thing?

#133 Re: Help Me ! » Follow-up on my last post » 2012-06-27 02:16:13

This is what I did

y = 8(0) + 123
y = 8
(0, 8)

so y - 123 = (x - 0)

#135 Re: Help Me ! » Follow-up on my last post » 2012-06-27 02:00:15

So, the point slope form is y - 123 = 8(x - 0) then?

#136 Re: Help Me ! » Follow-up on my last post » 2012-06-26 08:09:53

Oh and Thanks Bob Bundy, I understand how to find the points now! It's way easier then I thought it was, I had thought it was something much more complicated. big_smile

#137 Re: Help Me ! » Follow-up on my last post » 2012-06-26 08:02:11

I don't understand what BobbyM did to get the slope intercept form. I tried doing what he did with my correct points but I just don't get it. I need the slope intercept form to get the point-slope form..

#139 Re: Help Me ! » 2x + y= -6, How do you do this problem? » 2012-06-26 07:25:20

Thanks guys! I understand how you do this type now! I think I do anyway..

#141 Help Me ! » 2x + y= -6, How do you do this problem? » 2012-06-25 16:38:09

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What's the answer and how did you get it? I would like to understand how to do these problems without help. I just don't get it because I don't know how you do it if there isn't anything put for y.

#142 Re: Help Me ! » Standard Form of an Equation and Simplifying fractions! » 2012-06-25 16:36:01

3x + 3/2y= -9
3(0) + 3/2y= -9
0 + 3/2y= -9
3/2y = -9
3/2y = -9

Then I multiplied both sides of that fraction by 2 and got 6/4 and then I divided both sides by 3 and got 2/1.

I'm not sure what's next and if what I did so far is correct?

#143 Re: Help Me ! » Follow-up on my last post » 2012-06-25 16:33:20

The points are actually 1,115.00 and 5,83.00.

So I need to know the slope-intercept form of the equation that goes through these two points and how you got it!

And the point-slope form of the equation that goes through these two points and how you got it!

Sorry about that!

Also, what would the points be for y - 7 = 3(x + 2) and y - 2 = 3(x - 2) ? I don't understand how to do that because I don't know when I'm supposed to change the positive/negative signs.

#144 Help Me ! » Standard Form of an Equation and Simplifying fractions! » 2012-06-23 12:08:15

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I just need some help finding the intercepts in this problem. Except this one has a fraction and I don't know how to deal with it if it has a fraction.

This is the question:
5. 3x + 3/2y= -9

This is what I did so far for y:
3(0) + 3/2y= -9
0 + 3/2y= -9
3/2y = -9

So first I had to get it down to the 3/2y = -9, so that I can simplify that and get one of my points. However I don't know how to simplify
3/2y = -9. So, I need to simplify that so I have one of my points and then get the other one.

Hopefully this made sense! Thanks! smile

#145 Help Me ! » Follow-up on my last post » 2012-06-19 03:21:02

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Okay, so I understood what i was told in the last post that I posted, so I sent that work to my teacher.
For #2 and #5, I had been given the slope intercept form but I actually need point-slope form. So if somebody could get the answer to #2 and #5 and explain to me how they did it I would greatly appreciate it. Then on #12, she just simple said it was wrong and needs revision. I'm lost on that one and don't understand it..

2. Slope equals 2 and the line goes through the point (-1, 3)

(I need point-slope form)


5. The line goes through the points (1/2, 3/2) and (-1/4, 5/4)

(I need point-slope form)

12. Find the slope-intercept form of the equation that goes through these two points.

(The two points are 1,115.00 and 2,83.00.)

#147 Help Me ! » I Need Help With a Few Algebra Questions! » 2012-06-18 01:53:17

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Okay, so I've already done these questions a couple times and my teacher keeps telling me they're wrong without really telling me what I need to fix, just telling me where I messed up, the problem is I don't know how to do these problems correctly. So I'm coming here now!

The questions:
2. Slope equals 2 and the line goes through the point (-1, 3)
y + k = m(x - h)

(So for that one they just want you to get h and k and put 2 for the slope. I don't know how you find h and k with -1 and 3.)

5. The line goes through the points (1/2, 3/2) and (-1/4, 5/4)

(You have to do the same thing on this one, they just don't give you a slope.)

12. Find the slope-intercept form of the equation that goes through these two points.

(The two points are 1,115.00 and 2,83.00.)


So, I need somebody to give me the answers to those three problems and explain to me how they got the answer, because I want to understand how to do these problems, not just get the answer.

Thank you! smile

#148 Re: Help Me ! » Question Regarding Algebra and Simplifying » 2012-06-16 09:15:23

Thank you Bob Bundy and eterry! I appreciate it. I understand now! Thanks. smile

#149 Help Me ! » Question Regarding Algebra and Simplifying » 2012-06-13 04:11:14

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Okay, so I started reading the next lesson and a couple questions came up that I was hoping I could verify here.

The lesson states:

"Example 1: 2x + 3y = 6

  Step 1: put zero in for x and solve for y.

  2(0) + 3y = 6

  Simplify 2(0)

  0 + 3y = 6

  Simplify 0 + 3y

  3y = 6

Solve for y

3y =6

3    3

y = 2

The point is (0, 2)"


I understand what it's saying up until the, "Simplify 0 + 3y = 3y = 6" part. How is 3y simplified to 6? And then what happened here,
"3y =6
3    3
y = 2"

My last question is do you always put 0 in for x in an equation like this?

Thank you! smile

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