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(x1, y1) then it would be (1, 1).
I understand what the slope is and what the points are for a point-slope problem for example:
y-4= -3(x-2)
The slope of the equation is -3
The point from this equation is (2, 4)
And the same in slope-intercept.
And I understand how to get the slope-point form from two points. But 1,115.00 and 5,83.00 aren't my points, they're coordinates, right? And I don't know how you draw points from coordinates..
1,115 would be x1 right?
What do you mean "these are the points"? Isn't 1,115 just one point?
Yes.
What about y - 8920 = 8(x - 1,115) ?
I'm not sure if the answer is y - 123 = 8 (x - 1) but that's what I got.
So instead of 0 I could pick 1,115.00 and then do the same thing?
This is what I did
y = 8(0) + 123
y = 8
(0, 8)
so y - 123 = (x - 0)
So, the point slope form is y - 123 = 8(x - 0) then?
Oh and Thanks Bob Bundy, I understand how to find the points now! It's way easier then I thought it was, I had thought it was something much more complicated.
I don't understand what BobbyM did to get the slope intercept form. I tried doing what he did with my correct points but I just don't get it. I need the slope intercept form to get the point-slope form..
Thanks Bob Bundy!
Thanks guys! I understand how you do this type now! I think I do anyway..
Oh, it wants you to find the points!
What's the answer and how did you get it? I would like to understand how to do these problems without help. I just don't get it because I don't know how you do it if there isn't anything put for y.
3x + 3/2y= -9
3(0) + 3/2y= -9
0 + 3/2y= -9
3/2y = -9
3/2y = -9
Then I multiplied both sides of that fraction by 2 and got 6/4 and then I divided both sides by 3 and got 2/1.
I'm not sure what's next and if what I did so far is correct?
The points are actually 1,115.00 and 5,83.00.
So I need to know the slope-intercept form of the equation that goes through these two points and how you got it!
And the point-slope form of the equation that goes through these two points and how you got it!
Sorry about that!
Also, what would the points be for y - 7 = 3(x + 2) and y - 2 = 3(x - 2) ? I don't understand how to do that because I don't know when I'm supposed to change the positive/negative signs.
I just need some help finding the intercepts in this problem. Except this one has a fraction and I don't know how to deal with it if it has a fraction.
This is the question:
5. 3x + 3/2y= -9
This is what I did so far for y:
3(0) + 3/2y= -9
0 + 3/2y= -9
3/2y = -9
So first I had to get it down to the 3/2y = -9, so that I can simplify that and get one of my points. However I don't know how to simplify
3/2y = -9. So, I need to simplify that so I have one of my points and then get the other one.
Hopefully this made sense! Thanks!
Okay, so I understood what i was told in the last post that I posted, so I sent that work to my teacher.
For #2 and #5, I had been given the slope intercept form but I actually need point-slope form. So if somebody could get the answer to #2 and #5 and explain to me how they did it I would greatly appreciate it. Then on #12, she just simple said it was wrong and needs revision. I'm lost on that one and don't understand it..
2. Slope equals 2 and the line goes through the point (-1, 3)
(I need point-slope form)
5. The line goes through the points (1/2, 3/2) and (-1/4, 5/4)
(I need point-slope form)
12. Find the slope-intercept form of the equation that goes through these two points.
(The two points are 1,115.00 and 2,83.00.)
Haha, thanks BobbyM and Bob Bundy!
Okay, so I've already done these questions a couple times and my teacher keeps telling me they're wrong without really telling me what I need to fix, just telling me where I messed up, the problem is I don't know how to do these problems correctly. So I'm coming here now!
The questions:
2. Slope equals 2 and the line goes through the point (-1, 3)
y + k = m(x - h)
(So for that one they just want you to get h and k and put 2 for the slope. I don't know how you find h and k with -1 and 3.)
5. The line goes through the points (1/2, 3/2) and (-1/4, 5/4)
(You have to do the same thing on this one, they just don't give you a slope.)
12. Find the slope-intercept form of the equation that goes through these two points.
(The two points are 1,115.00 and 2,83.00.)
So, I need somebody to give me the answers to those three problems and explain to me how they got the answer, because I want to understand how to do these problems, not just get the answer.
Thank you!
Thank you Bob Bundy and eterry! I appreciate it. I understand now! Thanks.
Okay, so I started reading the next lesson and a couple questions came up that I was hoping I could verify here.
The lesson states:
"Example 1: 2x + 3y = 6
Step 1: put zero in for x and solve for y.
2(0) + 3y = 6
Simplify 2(0)
0 + 3y = 6
Simplify 0 + 3y
3y = 6
Solve for y
3y =6
3 3
y = 2
The point is (0, 2)"
I understand what it's saying up until the, "Simplify 0 + 3y = 3y = 6" part. How is 3y simplified to 6? And then what happened here,
"3y =6
3 3
y = 2"
My last question is do you always put 0 in for x in an equation like this?
Thank you!