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Thanks for the clarification MathisFun. Makes more sense now.
So therefore, when you're taking the square root of a variable, it can be positive or negative?
But if it's a constant, it's only positive, right?
That's what I figured and when I asked my pre-calculus teacher, he said it's only positive two because it's not a function or something like that.
http://www.mathisfunforum.com/viewtopic.php?id=7528
And according to this thread, the posters agree that it is only a positive number unless the square root has a
Any idea?
Alright so I was bored and always wondered this. I was looking at the Site Suggestions forum (I think) and I came across a thread named "What is a Function?" and something about square roots was mentioned.
So my question is, just for general knowledge:
For the first one, the answer is ONLY positive two, I believe. That is because we are asking for the positive square of 4. Correct?
But for the second one, the horizontal asymptotes are at y=2 and y=-2. Why is it that with the second one we have to consider the denominator as +/-
Thanks for having a look. I was just curious.
Like Bobbym said, there could be other interpretations of this series.
For example it could be a group of 3 going up by 1 and then squaring the last number minus 1.
So 2,3,4
15,16,17
288,289,290
84099, 84100,84101
Do you mean 0.519 dollars per share? If so:
4,000 * .519 = $2076
20,618 * .485 = $9999.73
11,904 * .425 = $5059.2
Add them all up and you get:
$2076 + $9999.73 + $5059.2 = $17,134.93
This is the cost of all the shares.
Now we take that number and divide it by the number of shares we have (32,522).
$17134.93/32522 = $0.526871963
Therefore, the average share price is 52.7 cents a share.
Not sure if this is correct but here it goes for #1:
Back into the equation.
I graphed it and it seemed to suit your description. Hopefully, someone can correct any mistakes I made.
Yup, I had a good look at it.
Took me a while to understand it all but I see the logic behind it.
Thanks for the taking the time to explain all the steps guys. I appreciate it.
I talked to my teacher about it and he said that the reason why we use a linear equation is because the remainder is always one degree lower than the divisor.
Divisor: (x-1)(x+2) = (x^2+x-2) which is a quadratic. So we want an equation that is one degree less than a quadratic, which would be a linear one.
Is that right?
Awesome, thanks a lot for the help. I don't know why you decided to divide a standard linear polynomial though. I would've NEVER thought of that.
Glad I stumbled across these forums, just for general purpose as math is awesome.
You said you always start with the lowest degree polynomial first. So if P(x) = mx +b did not work out, would you move to a quadratic equation next?
Alright so let me try to decipher this and you can tell me if I did this correctly or not.
y = mx+b is the standard form for a linear equation
So we divide the polynomial by a linear equation in the form (x-b) where b is equal to 1
(mx +b) / (x-1) = m with remainder m + b
(mx+b) / (x+2) = m with remainder -2m + b
We solve for the variable b in each case.
m + b = 2
b = 2-m
-2m + b = -19
b = 2m - 19
Let b = b and solve for m
2-m = 2m-19
3m = 21
m = 7
Substitute m = 7 into b = 2-m
b=2-m
b=2-7
b=-5
But these into the form P(x) = mx +b
P(x) = mx +b
P(x) = 7x -5
How's that?
That's the correct answer!
Bobby, would you be kind enough to post your steps here for reference so when exam time comes around, I'll know what to do?
It would be greatly appreciated. Thanks.
If you want to solve for m and x (respectively), you'll have to tell us what the other side is equal to.
Also, is it 9/(m+7) or (9/m)+7?
Well, here it goes.
Q: When a polynomial is divided by (x+2), the remainder is -19. When the same polynomial is divided by (x-1), the remainder is 2. Determine the remainder when the polynomial is divided by (x+2)(x-1).
Attempt: I got as far as P(-2) = -19 and P(1) = 2.
No clue where to go after that. It's not for homework or anything so I'm not terribly worried about it but it would be greatly awesome to find guidance on how to solve the problem. Thanks