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yup So its just talking about what happens to the rope when the goat goes around the barn but when I read the problem it doesn't make sense its annoying.
I am still confused so the base of the rectangular barn is 50 and the height is 20? the goat is tied in the (A) corner (of the circle u drew )
Ok I have 5 more to go but I cant picture it or draw it it's so confusing
If there is a goat tied to a rectangular barn on a 50 foot lead and the barn is 20 feet by 20 feet (floor), what is the maximum grazing area? If there are regions you can't find the area of, provide as good an estimate as you can. Assume the goat is tied to a corner outside the barn, cannot get in, and that the barn is not grazing area. (Remember, this will be based on parts of circles, no other shapes...the goat's rope will only get shorter when he tries to go around the barn...)
6. How much of the 50 foot circle can the goat reach without getting interrupted by the barn? What is that area?
7. When the rope goes around the barn, what is the new radius? How much of a circle can it make without hitting the barn or overlapping area you've already found? What is that area?
8. When the rope goes around the barn the other way, what is the new radius? How much of a circle can it make without hitting the barn or overlapping area you've already found? What is that area?
9. The areas you found in 7 and 8 overlap each other. How much do they overlap? What *approximate* shape do they make? What is that area?
10. What is the total grazing area the goat can reach?
Thank you sooooooooooooo much ![]()
R=5√2
then when I do the opposite
5^2√2 ^2* PI = 50 PI
ok so half the area of 100PI=50 PI
50PI ÷ PI = 50
√50 = 5√2 = Radius
so the area is 50 PI
square root of 25PI is 5PI
area= 100PI/2 = 50PI
radius= 50PI ÷ 2 = 25PI
OOOh So the radius would be 5 .
5. What is the radius of a half-piece? (ie, where do I need to cut to make two equal halves out of a piece?)
5- The radius stays the same 10 inches.
Oh OK so even if they were in half the area stays the same 100 pi .
Thanks Bob ![]()
So the same area 100 pi is the answer right?
my teacher said:
You should take the problem literally. What would the area of the "whole pizza be?"
#4- What would the area of the whole pizza be if it were made of half pieces?
does't that mean the same original pizza but with 32 pieces ?
3- 11.25/360 * pi* 10²= 25/8PI
22.5/360 *pi *100= 25/4pi
OoH I did that in the beginning I got 22.5
4. What would the area of the whole pizza be if it were made of half pieces? it mean the original pizza
2. What is the area of one piece of pizza? (10/360)[(PI)10^2] = 25/9 PI No. You want 1/16 of your answer to part 1.
2- confused isn't the Area of Sector = ½ × (θ × π/180) × r2 (when θ is in degrees)
the degree is 20 right? like I measured it from the circle you drew ½ × (θ × π/180) × r^2=
50/9 PI
Hi really stuck on these questions I did 3 left with 2 :
I have a pizza. The radius is 10 inches long. The pizza was cut into 16 equal slices. When 1 slice was left, my sister and I both wanted it, so we agreed to cut it in half, but I like the crust more than she does, so we decided to cut it the "other way." In other words, the two pieces would not be symmetrical. The inside piece would contain all topping, and the outer piece would contain some topping and some crust.
1. Find the area of the whole pizza. PI * r² = 100PI
2. What is the area of one piece of pizza? (10/360)[(PI)10^2] = 25/9 PI
3. What is the area of a half-piece?(5/360)[(PI)10^2] = 25/18 PI
4. What would the area of the whole pizza be if it were made of half pieces?
5. What is the radius of a half-piece? (ie, where do I need to cut to make two equal halves out of a piece?)
oooh I forgot the x
x²-18x+81
x²+-9x+-9x+81=
-9x+-9x= -18
x²-18+81
taraaaaaaaaa thank you ![]()
last -9*-9