You are not logged in.
Then that would be decimal numbers I think.
I think there is no number that 2 would raise to give 5, on the other hand, there is no number that 3 would raise to give 2
Unfortunately, the calculator I am using does not have base 3 and the rest, but only base 10
I see, it can not be solved
How about if the log of 5 had base 2 and the log of 2 had base 3, what would have been the answer?
Equal 1
How about log of 2 to the base 2?
It is also 1.
But you did not talk of the log2 base two.
The log5 base five is multiplying the log2 base two.
That is 1.
It means log five base five.
But a log of the same base is equal 1
Please I beg of you to show working.
Thank you
Please I wish you solve and that I learn:-)
Errr, okay - I see now.
Thank you Bobbym.
Please is it possible in the world of logarithm to have different bases at the same time? Like the following;
log5*log2 - the log5 is in base five and the log2 is in base two.
Many thanks!
In step 3, how did you get the 4 in the bracket?
Yes I do understand step two - but step 3 confounds me.
I am thinking of why the 4 in the bracket appeared, in step three.
Thanks for the confirmation.
Little algebra? Mmm, I'm confounded though.
So, should I take it from you that when bases at one side of an equation are the same one could equate the exponents regardless of the bases at the other side? As in the case this problem
Please confirm.
Bases are not the same why equating powers?
[I have long known that bases must be the same before powers are equated]
Yes, it gives 4 - I did not put brackets around the x-1 as in 3^(x-1) when doing the plugging, but apart from your previous steps is there no other way to solve this problem? - I am asking because your factoring seems wierd to me.
It gives 5, and not 4.
Why are you saying that? I was thinking it is correct
It seems you once solved this, but upon reconsideration I did it so;
3^x + 3^(x-1) = 4
3^x + 3^x/3 = 4
3^(x+1) + 3^x = 12
xlog3 + xlog3 + log3 = log12
x(log3 + log3) = log12 - log3
answer = log12 - log3/(log3+log3)
Is the answer correct?
You understand that?
yes I do - thank you Bobbym, I have cottoned on.