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#1482 Exercises » Complex Analysis » 2015-07-18 09:03:20

zetafunc
Replies: 21

In this thread, f is assumed to be a function mapping complex numbers to complex numbers, unless it is explicitly stated otherwise.

#1

Click here for the video solution.

#1483 Re: Help Me ! » Transformations » 2015-07-17 07:16:33

For 16, what do you think the scale factor was?

For 17, how can you apply what you did in 16? (Also, see 18-20 for a clue.)

For 18-20, is there a common scale factor for all three vertices?

#1484 Re: Guestbook » Guestbook » 2015-07-16 05:14:45

mathaholic wrote:

Square root of 2, 3, 5, so on...

How about √p, for p prime?

#1485 Re: Help Me ! » Indefinite Integrals » 2015-07-16 05:06:01

Use partial fractions. The integrand can be written as a sum of multiples of 1/x^6, 1/x^4, 1/x^2 and 1/(x^2 + 1). These can then of course be integrated term by term.

#1486 Re: Help Me ! » Mechanics » 2015-07-12 23:35:12

We can't give you what you need, because you haven't been specific enough. "Mechanics" is a very broad term: why not tell us exactly what is covered in your syllabus?

#1487 Re: Help Me ! » -i times i » 2015-07-12 23:26:50

The imaginary unit is defined as i² = -1.

Help! I found on mathsisfun about Imaginary Numbers that -i times i equals 1. May anyone please prove?

(-i)*(i) = -(i*i) = -(i²) = 1.

But, does that mean -i is the answer to √1?

By convention:

√1 = 1, by convention. However, the equation x² = 1 has two solutions, 1 and -1.

#1489 Re: Help Me ! » limits » 2015-06-24 11:20:32

There's an obvious choice of f(x): if you can't see it, try dividing by

. (It doesn't matter that this operation isn't valid for x = 0 -- your functional equation will certainly be satisfied for this function at 0.)

The initial condition restricts the choice of f.

Now plug f(x) into your limit, use the fact that log is a continuous function, and use L'Hopital a couple of times to get the answer.

#1490 Re: Dark Discussions at Cafe Infinity » Fiber Optics? » 2015-06-22 05:13:39

David wrote:

So... I switched to fiber optic internet and they are fast.

My ISP says the "light" travels at 300 000 000 km/s
Shouldn't it be slower? Considering it's travelling through a median. That means my ISP lied to me tongue

And for one moment I thought they managed to transfer data at the speed of light... (Which I did not, actually.)

It should also be m/s, unless your ISP has found a way of making light move at over a thousand times its upper bound... in which case, I'd like to sign up.

#1491 Re: Help Me ! » Really Hard Algebra Equations » 2015-06-19 06:51:34

For the first, you could factorise the LHS as (ab + 1)(a + b) = 8(a+b) = 80, i.e. a + b = 10. Then notice that (a + b)^2 = a^2 + 2ab + b^2.

For the second, there probably is some neat way of doing this, but you can do this easily with matrices (write in the form Ax = b, where A is a 5x5 matrix, x = (a,b,c,d,e), b = (177,154,146,138,165)).

For the third, take the equation p + q + r = 7 and multiply first by p, then q, then r to form 3 separate equations in p,q,r, then add them together. You can then re-arrange for pq + qr + rp.

#1492 Re: Help Me ! » L'hopital's Rule » 2015-06-19 01:48:26

That's one way, but you could note what happens for negative and positive x. Since cos(-x) = cos(x), then the function is negative for negative x, and positive for positive x (for x sufficiently close to 0).

You know it'll approach infinity (positive or negative) since cos(x) is bounded and 1/x goes to infinity as x goes to 0.

#1494 Re: Help Me ! » L'hopital's Rule » 2015-06-18 22:46:10

You can't apply L'Hopital a third time, because

is not an indeterminant form. In fact, with that limit, approaching 0 from the right and left gives you positive and negative infinity -- i.e. the limit doesn't exist.

#1495 Re: This is Cool » What's everyone working on? » 2015-06-17 07:01:33

But is that really any better than, say, the Sieve of Eratosthenes?

You would have thought knowing what a and b end in you could determine that a number is composite and therefore not prime, turns out it doesn't seem to work that way.

It wouldn't -- using your notation, x is prime iff (a,b) = (1, x) or (x,1). Even if a or b is 1 modulo 10, that doesn't guarantee that a or b is 1, and for large x, will give you a very large number of possibilities.

#1496 Re: This is Cool » What's everyone working on? » 2015-06-15 22:43:29

Primenumbers wrote:

I am working on finding a solution to proving whether a number is prime or not

Like this?

#1497 Re: Dark Discussions at Cafe Infinity » What is soy sauce? » 2015-06-14 05:14:38

A chip pan is a deep pan you use to deep fry things in. It's a portable, home-use version of what you might see employees using in a fried chicken shop to fry chips in (they put them in a metal basket and slowly lower them into the oil). You can fry other things aside from chips with a chip pan.

#1498 Re: Help Me ! » digit sum » 2015-06-14 00:18:42

bob bundy wrote:

I was hoping to reduce this to an algorithm.  There's no obvious pattern.  I have managed to construct a 'formula' for calculating the digit sum, but it can only be used if you already know the full set of digits so it doesn't really help much.

Transcending:  Did this arise from a question on a course?  In which case what method was the questioner expecting?  I had hoped to find an analytic way of solving this.

Bob

My best guess is that this is actually a number theory problem, and that the OP meant to write

2^12 = 4096 -> 4 + 0 + 9 + 6 = 19 -> 1 + 9 = 10 -> 1 + 0 = 1

Do this over the non-negative integer powers of 2, and you'll get a 6-periodic cycle, (1, 2, 4, 8, 7, 5). This can be proven.

#1499 Re: Help Me ! » simple logic yet difficult » 2015-06-13 21:00:29

In the linear algebra courses I've taken, it was common not to use any kind of formatting to distinguish between vectors, matrices, scalars, multilinear forms, etc. it simply became too tedious, and it was obvious from the context what each symbol meant. I personally tend to get more put off by all the decorative notation (especially when they start double-underlining or triple-hatting). As bob bundy said, there isn't any definite rule about this, but when dealing with numerous algebraic objects in the same context, these conventions tend to vanish.

However, if you're using just vectors and scalars, then I think a separate format for vectors would be appropriate.

How do you change a vector from magnitude-bearing form to component or coordinate form?

By 'magnitude-bearing form' I guess you mean a unit vector?

#1500 Re: Dark Discussions at Cafe Infinity » What is soy sauce? » 2015-06-13 08:39:32

Used to buy my soy sauce from Sainsbury's (they offer that meal deal thing where you can buy a sauce, noodles and a packet of veg for £3 for at least 2 people, i.e. one student), but I found I had to use so much of it to get the colour and flavour I wanted. I like the Amoy brand better because of that, it's sometimes on offer for £1 or something.

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