You are not logged in.
I have known it now - good!I need a little rest, so I will see you later. Sorry but I am exhausted.
You mean these, 3^(n+2) 3^(n+2) 3^(n+2)
Please have you tried multiplying 9^(n+2) 3^(n+2) back to get 27^(n+2)? And was it possible for you?
Is 27^(n+2) the same as 9^(n+2) 3^(n+2)?, If so I tried multiplying the latter expression back, but didn't get the former.
Please help with these.
Thank you
I see the difference now!
Thank you!
I was thinking they're the same, because according to the laws of exponents (ab)^2 is the same as (a^2^b2)
Is evident that the square(2) is multiplied to the variables. What do you say?
Yes, that is it!
And are they the same expression?
Regarding #1 the 'x' minus 'm' are all on one plateform, and the 'g' minus 'f' are the denominator
With respect to #2 the 'x' is squared and the 'm' is also squared a minus sign is in between, and are on one plateform which is over 'g' squared minus 'f' squared.
And my question is, are both #1 and #2 the same expression?
Thank you Bobbym!
Please these are confusing me;
(1)(x - m/g - f)^2
are the above the same as;
(2)x^2 - m^2/g^2- f^2
Please, confirm
Have an example?
The examples are not in the book I am using currently, but I will search for that particular book and then show you those examples.
Thanks Anonym
Why do you not want to move it?
Co's I have solved similar problems which I did not move any to RHS and then went on to solve the exponents after I have gotten rid of the bases
Quadratic idea? I see.
See what I mean;
3^2x+4 - 3^x+2 = 0
When you were solving you moved 3^x+2 to the RHS, and I am saying, in case you did not want to move 3^x+2 to the RHS how would you have equated the exponents?
Couldn't you have removed the 3's without moving 3^x+2 to the RHS?
3x^2x+4 - 3x ^x+2 = 0
With this, how would you have solved it if you don't want to move 3x^x+2 to the RHS?
I am not well versed in equating exponents, just trial and error;
2x + 4 + x + 2 = 0
3x + 6 = 0
3x = - 6
x = - 2 correct?
Are you implying the exponents shouldn't be equated?
Can you take the next step?
[Sorry - I was called away]
equating exponents
2x + 4 - x + 2 = 0
x + 6 = 0
x = - 6 correct?
So it meaes you multiplied 3^(x+1) by (3^(3+x) - 3)?
3^(x+2)
Please how did you multiplied the -3 with the rest?
3^(x+1) (3^(3+x) - 3) = 0
I wish you deal with the one at #510 for me
Thank you
Ok, I see now, good one
I am thinking others might say they not the same if it does not involve plugging in, because just -x+7 and 7-x are different answers - what do you say?
See this
7-x plugging 5 will be 7-5 = 2
And mine -x+7, plugging in 5 will be -5+7 = 2
I think both give the same answer 2