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#176 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-11-01 09:54:52

Acb = 30
Abc = 90
Bac = 60
Aob = 30
Abo = 60
Obc = 120
Boc =60

#178 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-11-01 09:10:53

Yes I own a protractor So that makes  Ab= 60 bc= 75

#179 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-11-01 08:20:41

14.I choose E- 15°

14. What is the measure of arc BC?
A 20 deg
B 45 deg
C 75 deg
D 120 deg
E 15 deg
F 90 deg

15- I choose E-Yes

15. Are arcs ABC and AC equal?
A maybe
B none of these
C kinda
D 55
E yes
F no

#180 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-11-01 08:02:58

It's an Acute Triangle so all the angles are less then 90.

Abo = 45
Obc = 45
Boc  = 15

And when I add 45+15+30+45+15+30= 180 So that makes it correct.

#181 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-11-01 05:36:47

14- E

14. What is the measure of arc BC?
A 20 deg
B45 deg
C75 deg
D120 deg
E 15 deg
F 90 deg

#182 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-11-01 05:31:27

So my answer would be the arc of AB= 30

#183 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-11-01 05:12:21

Acb = 30
Abc = 90
Bac = 60
Aob = 30
Abo = 90
Obc = 90
Boc = 60

#184 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-31 06:03:23

But weren't these talking about a central angle  The measure of a central angle is equal to the length of the arc it defines.  and we are talking about an inscribed angle now right ?

#185 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-31 04:22:51

13- The measure of an inscribed angle is equal to one-half the degree measure of its intercepted arc.

#186 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-31 01:12:16

#12- I choose 4(D) because the hypotenuse is two times that of the leg opposite the 30 degree angle. The leg opposite the 30 degree angle is 60 degree angle and the question said AB is 4 So, I multiply 4 * 2=8 and the radius = 1/2 * 8 = 4 So that is my answer.


12. If ABC is a 30-60-90 triangle, with angle ACB at 30 degrees, and line segment AC is the diameter of the circle, then if the length of line segment AB is 4, what is the radius of the circle?

A 8
B 2
C 10
D 4
E 7
F 16



#13- I choose A

13. Working with the information from 12 from here to #16, what is the measure of arc AB?
A 90 deg
B 25 deg
C 30 deg
D 120 deg
E 60 deg
F 72 deg

#14- F

14. What is the measure of arc BC?
A 20 deg
B 45 deg
C 75 deg
D 120 deg
E 15 deg
F 90 deg

15- E

15. Are arcs ABC and AC equal?
A maybe
Bnone of these
Ckinda
D55
E yes
F no

I was wondering how I can find that ?

16. What is the measure of chord BC?
A 6.928
B 2.098
C 5.281
D 10.112
E 9.475
F 7.461

#187 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 08:29:16

Hey again,

I answered #11 wondering if it's correct

#11- I choose C
11. What is the measure of arc AC?
A 54 deg
B 137 deg
C 180 deg
D 111 deg
E 174 deg
F 23 deg

#188 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 05:05:35

I have 10 more left but I am still working on then lol dizzy

#189 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 05:04:19

When I do to much math problems I sometimes get mixed up But thanks for the help guys !

#190 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 05:03:06

9 is the length of DJ and it is equal to 3√3 *√3

So the other side is 3√3 and the hypotenuse =  3√3 *2 which gives me 6√3 which is 6*sqrt(3)

I used the Special Right Triangles formula

#191 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 05:00:35

So I add the radius not the diameter to get the hypotenuse ?

#192 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 04:55:14

1 is the radius but the diameter is 2

#193 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 04:51:02

if it  1^2 + 1^2 = c^2 that makes my first  answer (b) correct

#194 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 04:48:51

but AM is 2 and Mi is 2  so isn't AI going to be 2^2+2^2

#195 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 04:34:09

#10 I like my answer (D) because I know that 9 is the length of DJ and it is equal to 3√3 *√3

So the other side is 3√3 and the hypotenuse =  3√3 *2 which gives me 6√3 which is 6*sqrt(3)

#196 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 04:33:03

So 2^2 +2^2= c^2
     4+4= c^2
     c^2=8
   sqrt 8

#198 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 04:02:59

lol sorry I posted that before reading post #31 Thank you ! big_smile

#199 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 04:01:33

So that makes it a right triangle So that means I  can use the Pythagorean theorum.

1^2 + b^2 = 2^2
1+b^2= 4

b^2= 4-1
b^2=3
b= √3

#200 Re: Help Me ! » Circles: Chords, Radii, and Arcs » 2012-10-30 03:51:40

ooooh but the radius of the circle is half the diameter So from M to c that is 2

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