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#176 Re: Help Me ! » circular motion... with a twist! » 2008-04-03 05:03:42

The only force which is considered valid is the force that exerted by an object which is directly connected with the other.

The cylinder exerted Mg on the cord, and the cord exerted Mg on the puck, so the direction of the force should be parellel with the direction of force on the cord which is pointed straight toward the center.

#177 Re: Help Me ! » Integration » 2008-03-18 04:38:49

Ouch!! Why didn't I think of that, lol. Thanks!!

#178 Help Me ! » Integration » 2008-03-18 03:47:39

Dragonshade
Replies: 2

I am having trouble with an integration
Thanks in advance!

I tried to do it by letting 

#179 Re: Help Me ! » help, Area of circle » 2008-01-17 05:46:01

how come ??
I use triangle , rectangle........n polygons to get the proximation of the area of the circle
triangle can be divided to 3 triangle ....rectangle 4...... n polgons be divided to n
each of these triangle has equal sides R(radius) and an angle 2pi/n between the two sides.

#180 Help Me ! » help, Area of circle » 2008-01-16 12:43:37

Dragonshade
Replies: 6

I try to find the area of a circle with the exhaustion method

Then how to calculate that limit of Sin(../n) x n ?

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