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Thanks a lot for the explanation. Now im clear. You have mentioned that I was confusing sequences for series and that is exactly the root of my confusion.
Thanks. It really helps to understand the topic when you have this kinds of discussions.
Im not sure I understand. if b_{k} diverges, how does it imply that a_{k} cannot converge? Isnt this implying that if a series diverges absolutely then it diverges conditionally? (Which is wrong).
For example. The alternating harmonic series converges:
So the alternating harmonic series diverges absolutely but it converges conditionally and my professor's solution implied that if it diverged absolutely then it must diverge conditionally (which is a contradiction):
Could you please clarify this for me? Im very confused.
I got my quiz back and my professor gave me full points. Remember that my final answer consisted of saying "this series diverges absolutely". I did know that if a series diverges absolutely you can't imply that it diverges conditionally.
Anyways, the solution he gave on the board was:
Since the limit is not equal to 0 then it diverges. So basically he used the Divergence Test which says that if the limit of the series is not 0 then the series diverges. I did use this test and I saw that it gave me 1 (which is probably why he gave me the full points) but I didnt draw any conclusions because I took the limit of just k/(k+1) and thats not the actual series. The actual series is alternating.
So from his conclusions and his answer on the board you can deduce this:
But isnt this wrong? b_k is the absolute of a_k so by finding that the limit of b_k is not equal to 0, your actually finding that b_k diverges. But b_k is the absolute of a_k and if a series diverges absolutely it doesnt imply it diverges conditionally.
So my professor is wrong?
Please tell me if you can't follow my reasoning as im very intrigued by this.
[when I started the series from k=0 it was just a mistake when writing the LaTeX code.]
If your confused. Im even more confused ![]()
Just kidding, I understand it all but this series topic just seems too broad. Theres like a zillion convergence tests to apply, and just deciding which one to use becomes a question of its own. I guess practice will solve that.
Anyways, this was a question in a quiz. Its 3 questions like this in 10 mins so my guess is that its not supposed to be that complex. Maybe we are missing something?
Anyways, from my conclusions I answered that the series diverges *absolutely* which is true. I know this doesnt imply it diverges.
If a series converges absolutely then it converges, but if it diverges absolutely you cannot imply it diverges.
An example will be the alternating harmonic series:
so Bk is the harmonikc series which diverges which implies that Ak diverges absolutely but it doesnt imply it diverges since we know that the alternating harmonic series converges to ln(2) if im not mistaken.
So I was given an alternating series:
According to my book, given an alternating series, theres 2 types of convergence tests to apply.
So if:
Then the series converges.
So I saw that Ak decreases, but its limit is not equal to 0, its equal to 1. So this test is inconclusive.
Second test for alternating series to to do the abs ratio test. I went on to take the abs of the series:
So:
So the limit is equal to 1 as well and this test is inconclusive. If the limit was <1 then I could say that the series converges absolutely which implies that it converges. But it doesnt.
So we have:
The harmonic series diverges so Ak diverges as well so in my quiz I just said that the series diverges absolutely. Is this right?
All good.
I always do all my homeworks watching House MD or The Big Bang Theory episodes.. Love both shows.
I've never understood it. Like, it just seems something I would had done when I was 8yrs old and not now...Dont know.
No problem. Been there myself.
Anyways, if you rotate around y=1 (are you sure this time??? lol
) then what changes is the radius of the solid. So before the radius was "y" but now since we are rotating around y=1 then the new radius is "y-1" and not "1-y" like you said. So the resultant integral would be:
What you have to realize is that in the initial problem you said to rotate around the x-axis which is the same as rotating around y=0. In which case we setup the integral as dy. If you now rotate around x=1 then the integral changes to dx and it changes completely.
Rotating the graph around x=1 or y=1 or y=2 is completely different.
Can you please specify? Im confused.
You cant rotate it around y=2. It cuts the graph. You would have to rotate it around the x-axis (y=0) or around y = negative
You mean changing x=1, x=4 to x=2, x=4?
No problem. Pleasure to help you.
Thanks Dragonshade for confirming I was right.
Depends on how many digits your willing to calculate pi with.
Brain fart.... how?
Its just algebra. Nothing to do with calculus.
Do you see it now?
Yes I can go from:
to:
because algebraically they are equal.
What your doing is the same thing.
Your right. My bad.
So:
So the integral that we setup is in this form:
To be honest, im not sure myself I did it right. Feel free to find any errors on my part because I want to know myself if I did it right. This solids of revolutions were always tricky ![]()
I quit playing my Xbox360 to play WoW (World of Warcraft).
I had to quit or I was going to fail the semester...
The formula to find the volume of a solid using the shell method is this:
So to set up your integral it would be like this:
Did you make me a Real Member yet?
Yes please. I would appreciate it.
I was going to say to send a Private Message but then i saw this site doesnt have PMs ??? Why>?
(d) equal number of 0s and 1s.
Since its length 10 and its equal numbers then the string has to contain 5 0s and 5 1s. I tried to think of it as one group of 0s and one group of 1s. The way you can arrange the group of 0s is 5! and the way you can arrange the group of 1s is 5! as well. You can also flip this two groups so I thought my answer was:
2 * 5! * 5! = 480
but its wrong.
How do you think of this?
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A coin is flipped 10 times. How many possible outcomes?
(a) in total
(b) exactly two heads
(c) at most three tails
(d) contain the same number of tails and heads.
I found (a) to be 2^10 but I have no idea how to do the rest?
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How many subsets with more than 2 elements does a set with 100 elements have?
A set with 100 elements has 2^100 subsets. But how do I find how many subsets with more than 2 elements?
I tried to think of it like this, total subsets is 2^100 so if I want how many subsets with more than 2 elements then it would be:
2^100 - (subsets with no elements) - (subsets with 1 element) - (subsets with 2 elements)
2^100 - 2^0 - 2^1 - 2^2
2^100 - 1 - 2 - 4
2^100 - 7
but its wrong. Could anyone help me with all this questions?
So here i am just digging up your post again.
What was your score on the test? Did you graduate yet?
Also, when should one take the GRE subject test? Junior or Senior?
Meh.
I was just playing with my stupid engine and the game went on like this:
e4 d6
f4 Na6
Nf3 Rb8
Bxa6 Ra8
Even if my evaluation function is as simple as you can get, when its searching, guiding itself by my eval function, why did it find Ra8 to be "better" than bxa6? If I understand this alpha-beta searching, the search function is supposed to evaluate every single position, bxa6 is supposed to give a higher score than Ra8 since with any other move that isnt bxa6 the score goes down by 3...
Hmm.