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#1 2008-08-15 19:59:25

tony123
Member
Registered: 2007-08-03
Posts: 229

Solve in natural numbers:

Solve in natural numbers:

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#2 2008-08-16 00:26:48

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Solve in natural numbers:

By inspection, two solution sets would be (1,1,x) and (x,1,1).
I can't see any others or prove that there aren't any though.


Why did the vector cross the road?
It wanted to be normal.

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#3 2008-08-16 07:07:54

LQ
Real Member
Registered: 2006-12-04
Posts: 1,285

Re: Solve in natural numbers:

First we put all things on one side:
a^b + b^c - 1 - a^c = 0
Then we integrate both sides that has matrixes of integers:
F(a^b) + F(b^c) - n - F(a^b) = C
That is allready the answer, C.
Just to prove my point. I didn't know what C was when I started counting on that.
The integral of every thing is the answer of what it is!


I see clearly now, the universe have the black dots, Thus I am on my way of inventing this remedy...

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#4 2008-08-16 07:09:15

Daniel123
Member
Registered: 2007-05-23
Posts: 663

Re: Solve in natural numbers:

LQ wrote:

First we put all things on one side:
a^b + b^c - 1 - a^c = 0
Then we integrate both sides that has matrixes of integers:
F(a^b) + F(b^c) - n - F(a^b) = C
That is allready the answer, C.
Just to prove my point. I didn't know what C was when I started counting on that.
The integral of every thing is the answer of what it is!

Hmmm?

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