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Can someone give me a proof of the following inequality
(p+q)(q+r)(r+p) ≥ 8pqr
mickeen
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aritmetic mean
geometric meanthanks
Last edited by nurshodiq (2009-04-24 01:24:17)
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Thanks for that but I dont really understand it. Can you five some explanation I can understand?
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Hi Mickeen;
If p,q, and r are greater than 0 than there is a longer proof that only uses algebra and a little calculus.
Expand the left hand side:
(A)
subtract
from both sidesDivide both sides by
group the left hand side like this
Now look at the first bracket. It is the sum of a fraction and its reciprocal. We can think of it as
Try to prove that this function is always >= to 2. Take the derivative and set it to 0
solve the equation:
disregard the negative root and plug the 1 into
You get 2. Determine that x=1 is a minimum by the second derivative or by graphing the function. So now we know that the first bracketed term is >= 2. We can do the same thing for the remaining 2 bracketed terms. We have 3 terms all >= 2: The sum of them is >= 6. We have proven this:
This implies (A) for p,q and r >0
Last edited by bobbym (2009-04-28 04:12:43)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Bobbym, thanks for that! I can understand it better now.
mickeen
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Hi mickeen;
Also the inequality is not true for negative numbers.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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That is a great proof, thanks bobbym, I learnt a lot from that.
However, is there a way to find the minimum of
without calculus?
Thanks also nurshodiq, I'm not that familiar with AMGM but it's interesting.
Last edited by Identity (2009-04-21 20:36:38)
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Your welcome, glad it helped.
There are ways of getting that minimum without calculus but if I mention any of them I would be leaving myself wide open to much deserved criticism. There is a book by Ivan Niven that covers this particular subject.
Thanks for looking at the post.
See nurshodiqs good idea below!
Last edited by bobbym (2009-04-27 01:33:59)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Thanks very much for all of the above. Very good. Can someone give me a proof of the following inequality please?
x^4 + y^4 + z^4 + w^4 ≥ 4xyzw
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we have aritmetic mean (AM) and Geometric mean (GM)
and
so for this problem we have
and both multiple by 4
thanks
Last edited by nurshodiq (2009-04-27 02:20:07)
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to find the minimum of
Last edited by nurshodiq (2009-04-27 00:44:16)
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Good way to find the minimum without Calculus, Thanks
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Nurshodiq, thanks for that
But how do we know that the
aritmetic mean ≥ geometric mean
or is there a proof of it?
Mickeen
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I think Wikipedia has a proof of the AMGM inequality by mathematical induction.
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Here it is:
http://en.wikipedia.org/wiki/Inequality_of_arithmetic_and_geometric_means
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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