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Hi Jane;
First 2 things:
1) Are you sure that this is new? Just asking because there are a lot of these.
2) Like to see the proof.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Bobby is right, this is related to Happy Numbers.
A number is defined as Happy if it eventually goes to 1, and Unhappy if it eventually goes to the loop.
Why did the vector cross the road?
It wanted to be normal.
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I know Soroban has done one for cubes. If hes already done this for squares, then my apologies my search didnt turn up anything similar from Soroban.
Im not one hundred per cent about my proof yet if I do manage a proof, it probably wont be a rigorous one.
Last edited by JaneFairfax (2009-10-11 11:34:12)
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Bobby is right, this is related to Happy Numbers.
A number is defined as Happy if it eventually goes to 1, and Unhappy if it eventually goes to the loop.
Yup.
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There is a simple prove to this.
Firstly
This means that a number will always go under 4 digits and loops can only contain numbers between 1-3 digits.
So test all numbers (proof by exaustion) below a 1000 and that's the proof
Last edited by wintersolstice (2009-10-17 02:19:35)
Why did the chicken cross the Mobius Band?
To get to the other ...um...!!!
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You'd also need to show that 81n < 10^(n-1), for n ≥ 4.
That's not a problem though.
Why did the vector cross the road?
It wanted to be normal.
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You'd also need to show that 81n < 10^(n-1), for n ≥ 4.
That's not a problem though.
Thanks:D I knew my proof was a little incomplete, I just wasn't sure was else was needed
Why did the chicken cross the Mobius Band?
To get to the other ...um...!!!
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