Math Is Fun Forum

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

*facepalm* man, I'm sorry this must be frustrating...

okay so what now?

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

What did you get?

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

y - 2 + 2/7 = (-1/7)x

2 + 2/7 is 2.28571429?

Is that normal? Do I round that?

Last edited by misheeru (2010-06-11 14:08:25)

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

-2 + 2 / 7.

-2 is -14 / 7 so -14/7 + 2/7 = -12 / 7

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

okay so we're left with: y - 12/7 = (-1/7)x?

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

Yep:

Add (1/7) x  to both sides.

---

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

since the deniminators are the same I don't need to change the fraction around? Is it just 17/7?

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

y - 12/7  =   (-1/7)x

+  (1/7)x    + (1/7) x
--------------------------

y - 12/7 + (1/7)x = 0

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

wow, I'm sorry, I'm not getting this one at all, I have no Idea what to do next...

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

Did you follow what I did above?

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

okay, yeah. I see now.

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

Now add ( 12 / 7 ) to both sides.

    y - 12/7 + (1/7)x  =  0

   +    12 / 7                + 12 / 7
---------------------------------------
y + ( 1 / 7 ) x          =  12 / 7        Now switch

( 1 / 7 ) x + y   =  12 / 7

Now check.

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

how? I'm bad with fractions.... just so you know

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

You start with:

    y - 12 / 7 + (1/7)x  =  0 Now add 12 / 7 to both sides.

    y - 12 / 7 + (1/7)x + 12 / 7   =  0 + 12 / 7

The - and + 12 / 7 cancel on the left.

    y  + (1 / 7)x  =  12 / 7 switch the x and the y on the left.

    (1/7)x + y   =  12 / 7 you are done!

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

I see how you got that now, but heres the problem: that answer doesn't fit in the answer box! Is there anyway to shorten it?

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

Yes multiply both sides by 7 to clear the denominators.

7*( (1/7)x + y )  =  7 * ( 12 / 7 )

x + 7y = 12 is that better?

---

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

yep! Wow, your a genius! I'd never have figured that out in a million years!!! Jeez that one had a lot of steps!

Thank you!!! No I will try one.. hopefuly I will get farther this time...okay?

(4, 6), (1, 5), are my points

I'll work on the slope, now. gimme a sec

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

Did you figure the slope yet? Are you stuck?

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

No...just alot going on. Sorry, noyt trying to waste your time...

is it -1/-3?

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

Yes, you can simplify that.

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

how? Do I divide?

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

You can multiply the numerator (top) and the denominator (bottom) by the same thing and not change the fraction's value, so multiply top and bottom by -1.

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

oh okay, so that way we get rid of the negative.

so then we have

y - 6 = 1/3( x - 4)?

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Of Moons, Birds and Monsters

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Area problems Please Help!!

Multiply both sides by 3:

3(y - 6 )= 3 * 1/3( x - 4)

3y - 18 = x - 4

3y - 14 = x

-14 = x - 3y

x - 3y = - 14

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

misheeru

Member

Registered: 2010-02-18

Posts: 4,594

Re: Area problems Please Help!!

Like this?

y - 6 = (1/3)x - 5/3???

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Of Moons, Birds and Monsters