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#51 2010-05-07 07:57:56

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Hi jerry;

Welcome to the forum.

Misheeru, I know that phrase!

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#52 2010-05-18 09:20:36

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

Ack! Hey bobbym, Sorry I didn't know!

I'm having trouble with this:
A regular hexagon with sides of 3" is inscribed in a circle. Find the area of a segment formed by a side of the hexagon and the circle.

I did one similar to this one and it was:

Find the area of one segment formed by a square with sides of 6" inscribed in a circle.

And got: 9/2π - 9

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#53 2010-05-18 09:28:35

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Let me see your work, because I am not getting that for your square problem.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#54 2010-05-18 09:49:23

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

Okay so to find the area of a segment, we subtract the area of a triangle from the area of a sector.

Find the area of one segment formed by a square with sides of 6" inscribed in a circle.


90/360π (3√2)

1/4π 9(2)

18/4π - 1/2 6(3)

Answer: 9/2π - 9 inches^2

Of Moons, Birds and Monsters

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#55 2010-05-18 09:56:07

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Hi;

Is that what you are saying it is? Your first line.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#56 2010-05-18 09:57:39

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

Yeah

Wait are you asking if thats my answer? If so then no.

Last edited by misheeru (2010-05-18 09:58:33)

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#57 2010-05-18 09:59:49

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Is that what you mean by this:


90/360π (3√2)

This is how I see that:

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#58 2010-05-18 10:01:09

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

yes. Thats what it is.

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#59 2010-05-18 10:01:45

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Then your final answer is not right.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#60 2010-05-18 10:04:57

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

Okay can you explain it to me then? Oh I forgot squared too. If that helps.

Its supposed to be: 90/360π (3√2)^2

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#61 2010-05-18 10:12:53

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Show me the formula you are using.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#62 2010-05-18 10:30:28

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

We use this: the area of the sector minus the area of the traingle = the area of the segment.

*Find the area of one segment formed by a square with sides of 6" inscribed in a circle.

I think I made a mistake in explaining the first time...Hold on... okay hows this:

The triangle forms a 90° angle.

Area of a sector = (Angle/360°) πr²                 Area of a Triangle: 1/2 BH
                                                                                 
                           (90°/360°)π3²                                1/2 6 (3)
   
                           (1/4)π 9                                          =9
                         
                             = 18/4π

                             = 9/2π

Final: 9/2π - 9

I think I see now, my work is all jumbled up on the paper I believe the (3√2) I put earlier was the Hypotenuese for the triangle. Sorry about that! I copied from my paper without thinking! Sorry! sad

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#63 2010-05-18 10:32:32

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

No problem. I am supposed to see that. That answer is correct. Good work!

CYA

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#64 2010-05-18 10:36:07

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

Wait! that wasn't the one I was stuck on!

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#65 2010-05-18 10:38:30

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Well go ahead what do you need?

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#66 2010-05-18 10:41:01

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

Geez I'm sorry I'll try to go fast!

Its the one I posted previously:

A regular hexagon with sides of 3" is inscribed in a circle. Find the area of a segment formed by a side of the hexagon and the circle.

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#67 2010-05-18 10:41:49

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

I get 3 is also the radius. What do you get for an answer?

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#68 2010-05-18 10:44:21

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

Okay so then do we start out  with finding the area of the sector? Idk i'm having trouble getting started on this one

Last edited by misheeru (2010-05-18 10:45:08)

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#69 2010-05-18 10:47:42

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Your formulas please I use different ones. What do they have you using?

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#70 2010-05-18 10:51:54

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

Well the teacher told me before to draw it out, find the area of the triangle by dividing it in half, then using that to find the hieght. So in this case the base of our triangle is 3, right?

Last edited by misheeru (2010-05-18 10:52:48)

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#71 2010-05-18 10:52:54

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

yes

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#72 2010-05-18 10:54:05

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

then half of that would be... 1.5?

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#73 2010-05-18 10:54:30

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Okay

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#74 2010-05-18 10:56:30

misheeru
Member
Registered: 2010-02-18
Posts: 4,594

Re: Area problems Please Help!!

Then.... the long side, isn't it supposed to be the {short side√ 3}? Or is that the hypoteneuse? Or is the hypotentuese supposed to be the short side*2?

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#75 2010-05-18 11:01:47

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Area problems Please Help!!

Do you see the triangle you are trying to figure, what are you trying to get?

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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