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Give triangle ABC and EDC, c is the midpoint of
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BD and AE.
prove: AB|| DE
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∠ ACB = ∠ DCE (vertically oppsite ∠s)
AC/DC = BC/EC = 1/2 (given)
∴ ACB∼DCE (SAS similarity)
∴ ∠ABC = ∠DCE
AB||DE (alternate angles are equal)
If two or more thoughts intersect, there has to be a point!
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