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Hi bobbym, thanks very much for that, I'll have a try myself
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Hi bubokribuck;
See if you can get y(.2) on your own.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym, I got y(0.2)=0.122826... , is it correct?
By the way, shouldn't p'=0.2y'(1-y^2)-y? The answers are slightly different this way, I got y(0.1)=0.109198 and y(0.2)=0.117486. Would you check it for me please. Thanks!
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Hi bubokribuck;
Very good you are correct about the missing y'! Please let me see your calculation of y(.1) and y(.2)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi, here's my calculations:
Also, how can I find the analytical solution for the problem please?
Last edited by bubokribuck (2012-04-22 07:00:34)
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Hi;
I would do this step last and not first
because you start with x0.
An analytical solution is unlikely. This DE has non linear terms y^2 and y'y.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi, is there any analytical solution for the following problems please?
If there is any, how can I find it please?
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Hi;
For the first one I had mathematica run it off:
is a solution.
The second one has non linear terms in it so again no analytical answer.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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