Math

Derick Mixon · 2013-09-19 01:07:56

Can you show me how you would solve this? I have the answers is you want to see them

bobbym · 2013-09-19 02:39:40

Start by doing the subtraction on the left side.

Now cross multiply.

Factor,

You have x = 0 and x = -2. We reject the 0 solution so x = -2.

Derick Mixon · 2013-09-19 03:54:28

1/2 right?

bobbym · 2013-09-19 03:58:16

For the first one?

Derick Mixon · 2013-09-19 03:59:15

yes

bobbym · 2013-09-19 04:00:42

In post #77 I solved it already, the answer is -2.

Derick Mixon · 2013-09-19 04:03:12

ok youre right I see It now what abou the next one

Last edited by Derick Mixon (2013-09-19 04:04:48)

bobbym · 2013-09-19 04:04:54

Give me some time to do the other ones. I will post them right here.

Derick Mixon · 2013-09-19 04:06:50

ok thanks

bobbym · 2013-09-19 04:40:41

Multiply both sides by 20.

Clean it up.

Add 8 to both sides.

Subtract 5x from both sides.

Divide both sides by 15 and you get x = - ( 17 / 15).

Derick Mixon · 2013-09-19 05:17:10

I have that as well. ok the next question

bobbym · 2013-09-19 09:45:36

Times both sides by 24.

Add 9 to both sides.

Subtract 8x from both sides.

x = 1

Derick Mixon · 2013-09-19 11:51:36

are you done for the night?

bobbym · 2013-09-19 14:20:39

Hi;

Yes, I am going to eat.

Derick Mixon · 2013-09-20 00:37:08

Did you do the rest yet?

bobbym · 2013-09-20 00:40:34

Take 1 / 9 away from both sides.

Flip them both,

x = 3

For the last one:

Times both sides by 15x.

Divide both sides 4.

x = ( 14 / 4 ) = ( 7 / 2 )

Derick Mixon · 2013-09-21 05:17:02

Are you in today?

bobbym · 2013-09-21 05:19:51

Yes, I am.

Derick Mixon · 2013-09-21 05:45:47

State the domain of y = x2

State the range of y = x2

State the domain of y = x2 + 2

State the range of y = x2 + 2

State the domain of y = 2x2 + 3

State the range of y = 2x2 + 3

State the domain of y = x2 5

State the range of y = x2 - 5

State the domain of y = -x2

State the range of y = x2

Derick Mixon · 2013-09-21 05:54:31

Can you show me how to solve them?

bobbym · 2013-09-21 05:57:29

What is x2?

Derick Mixon · 2013-09-21 06:24:06

The x value

bobbym · 2013-09-21 06:28:58

And the 2, is that a power?

Derick Mixon · 2013-09-21 11:18:22

yes

bobbym · 2013-09-23 08:26:49

State the domain of y = x^2

State the range of y = x^2

I get the domain as R and the range as [0,∞)

State the domain of y = x^2 + 2

State the range of y = x^2 + 2

Domain is R and the range is all positive reals greater than or equal to 2.

Math Is Fun Forum

#76 2013-09-19 01:07:56

Re: Math

#77 2013-09-19 02:39:40

Re: Math

#78 2013-09-19 03:54:28

Re: Math

#79 2013-09-19 03:58:16

Re: Math

#80 2013-09-19 03:59:15

Re: Math

#81 2013-09-19 04:00:42

Re: Math

#82 2013-09-19 04:03:12

Re: Math

#83 2013-09-19 04:04:54

Re: Math

#84 2013-09-19 04:06:50

Re: Math

#85 2013-09-19 04:40:41

Re: Math

#86 2013-09-19 05:17:10

Re: Math

#87 2013-09-19 09:45:36

Re: Math

#88 2013-09-19 11:51:36

Re: Math

#89 2013-09-19 14:20:39

Re: Math

#90 2013-09-20 00:37:08

Re: Math

#91 2013-09-20 00:40:34

Re: Math

#92 2013-09-21 05:17:02

Re: Math

#93 2013-09-21 05:19:51

Re: Math

#94 2013-09-21 05:45:47

Re: Math

#95 2013-09-21 05:54:31

Re: Math

#96 2013-09-21 05:57:29

Re: Math

#97 2013-09-21 06:24:06

Re: Math

#98 2013-09-21 06:28:58

Re: Math

#99 2013-09-21 11:18:22

Re: Math

#100 2013-09-23 08:26:49

Re: Math

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