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Whatever done to a Mersenne number to get to zero must be able to be done to it’s factors.
Mersenne Number= 2^11 -1
Factors = 23 and 89
2^11 -1 takes eleven goes to get to zero if I continually minus one and divide by 2. Watch what happens to 23 and 89 acting as remainders as I do the same to them.
2^11 -1
2^10 -1 First go
2^9 -1 Second go
2^8 -1 Third go
2^7 -1 Fourth go
2^6 -1 Fifth go
2^5 -1 Sixth go
2^4 -1 Seventh go
2^3 -1 Eighth go
2^2 -1 Ninth go
2-1 Tenth go
1-1=0 Eleventh go
23
(23-1)/2 = 11 First go
(11-1)/2 = 5 Second go
(5-1)/2 = 2 Third go
23+2 = 25, (25-1)/2 = 12 Fourth go
23+12 = 35, (35-1)/2 = 17 Fifth go
(17-1)/2 = 8 Sixth go
23+8 = 31, (31-1)/2 = 15 Seventh go
(15-1)/2 = 7 Eighth go
(7-1)/2 = 3 Ninth go
(3-1)/2 = 1 Tenth go
(1-1)/2 = 0 Eleventh go
89
8(89-1)/2 = 44 First go
89+44 = 133, (133-1/2) = 66 Second go
89+66 = 155, (155-1)/2 = 77 Third go
(77-1)/2 = 38 Fourth go
89+38 = 127, (127-1)/2 = 63 Fifth go
(63-1)/2 = 31 Sixth go
(31-1)/2 = 15 Seventh go
(15-1)/2 = 7 Eighth go
(7-1)/2 = 3 Ninth go
(3-1)/2 = 1 Tenth go
(1-1)/2 = 0 Eleventh go
They both take eleven goes to get to zero too.
Working backwards it can be seen that this must be the case. Starting with zero I multiply by 2 and add one continually until I get to 2^11 -1. The same must be done to the remainders which will then become 23 and 89 or zero, the factors of 2^11 -1.
Let the number of goes an odd number, y, takes to get to zero by continually minusing one and dividing by 2, (adding y when even) =z.
The z for 2^11 -1, 23 and 89 =11.
Whatever z equals for y, 2^z -1 must be factorable by y. When we use the method for 2^z -1, we never add 2^z -1 as it never equals an even number. This could potentially alter remainders for potential factors, but for Mersenne Numbers, this is not the case.
"Time not important. Only life important." - The Fifth Element 1997
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