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I designed a server sytem and its backup plan.
To simplify, there are a pair of server programs each using one hard server.
And redundancy makes a pair of them.
This is the original plan:
A1 A2
| |
B1 B2
But since A's are equivalent and B's are equivalent I come up this:
A1 A2
| X |
B1 B2
A1-B2 and A2-B1 also works.
Now comes the fun part: reliability
Suppose the manufacturer can only guarantee the failure rate of each hard server as little as p
How is the overall A-B server system failure rate?
For the straight pair, the failure situation is not a single pair could work (They both fail)
[1-(1-p)(1-p)]^2 = [p(2-p)]^2
For the cross enhanced, the success situation is both A's and B's have at least one functional:
[1-pp]^2
So the survival rate of the straight is S(p) = 1 - [p(2-p)]^2 ; failure rate s(p) = [p(2-p)]^2
the survival rate of cross enhanced is C(p) = [1-pp]^2 ; failure rate c(p) = 1 - (1-pp)^2
Usually, s(p) = 2c(p)
Or the cross pairing reduces the original failure rate by half.
X'(y-Xβ)=0
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s(p)/c(p) -> 2 as p->0
X'(y-Xβ)=0
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