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A bullet with a mass of 20 grams is horizontally fired at a body with a mass of 100 grams, suspended by a string with a length of 6 meters, . The bullet comes to rest in the body. Find the vertical distance that the combined system of the body and the bullet moves after the collision
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It seems you forgot to add the initial speed of the bullet.
I guess this speed is also assumed constant (no friction).
Last edited by KerimF (2024-01-10 19:28:18)
Every living thing has no choice but to execute its pre-programmed instructions embedded in it (known as instincts).
But only a human may have the freedom and ability to oppose his natural robotic nature.
But, by opposing it, such a human becomes no more of this world.
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It seems you forgot to add the initial speed of the bullet.
I guess this speed is also assumed constant (no friction).
Im sorry v=58.8m/s
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I think you can do this by energy.
First use mv = (m +M)V to calculate the velocity of the combined mass.
So initial kinetic energy = 1/2 (m + M) V^2
If it rises to a height of h above the start position, then all this energy is converted to potential energy = (m + M)gh.
My only worry about this is I haven't used the length of the string.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Kinetic energy = K.E. = m*v^2/2
Potential gravitational energy = P.E. = (m+M)*g*h
Based on the energy conservation, we can write (since the exercise is about an ideal situation):
m*v^2/2 = (m+M)*g*h
therefore:
h = m*v^2/(m+M)/g/2
Every living thing has no choice but to execute its pre-programmed instructions embedded in it (known as instincts).
But only a human may have the freedom and ability to oppose his natural robotic nature.
But, by opposing it, such a human becomes no more of this world.
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