Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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#1 2007-02-22 05:17:27

Sekky
Member
Registered: 2007-01-12
Posts: 181

Deleted

Deleted

Last edited by Sekky (2024-07-03 22:25:48)

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#2 2007-02-22 08:21:56

espeon
Real Member
Registered: 2006-02-05
Posts: 2,586

Re: Deleted

Hi Dan! Nice to know you appreciate and see potential in this website! Thanks for your generous and positive comment! Welcome to the forum and we hope you get to meet new friends and have fun here! Be sure to check out Help me if you're stuck and the members forum to find all sorts of news!

( I have absolutely no idea the stuff you were talking about lmao! I'm only 12 years old but i can still probably attempt at some parts. geometry shapes?)


Presenting the Prinny dance.
Take this dood! Huh doood!!! HUH DOOOOD!?!? DOOD HUH!!!!!! DOOOOOOOOOOOOOOOOOOOOOOOOOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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#3 2007-02-22 08:27:51

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,713

Re: Deleted

Welcome, Sekky! Impressive study list.

Had a look around your website ... I like your Flashmatics project.

And ... we noticed the "Nullity" story, too and talked about it here: http://www.mathsisfun.com/forum/viewtopic.php?id=5329

We have a wide community here (I like to think of it as a Village smile), so be prepared to enter all kinds of discussions from simple to advanced  to pure opinion.


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#4 2007-02-22 09:49:55

Zach
Member
Registered: 2005-03-23
Posts: 2,075

Re: Deleted

Why is the message about you, yet the subject is telling people to kneel before me?


Boy let me tell you what:
I bet you didn't know it, but I'm a fiddle player too.
And if you'd care to take a dare, I'll make a bet with you.

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#5 2007-02-22 10:02:43

Zach
Member
Registered: 2005-03-23
Posts: 2,075

Re: Deleted

kthxsekky


Boy let me tell you what:
I bet you didn't know it, but I'm a fiddle player too.
And if you'd care to take a dare, I'll make a bet with you.

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#6 2007-02-22 10:29:21

espeon
Real Member
Registered: 2006-02-05
Posts: 2,586

Re: Deleted

wow... Zach got told lol! GO SEKKY! WOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO
OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO!!!

Anyway I like simple math so i dont have to do anything troublesome lol! i usually like coordinates,
algebra( thats not too advanced but i still can use it)
and probability.

MWAHAHAHAHA ZACH GOT TOLD! MAJOR MAJOR POPULARITY DROP!

sozzy thats really mean of me. Sekky he didnt really mean anything bad. Its just a joke within the speech. He's always like that ^_^ and thats why we all love him! ^_^. poor poor Zach. But then again knowing him he wont like pity ^_^


Presenting the Prinny dance.
Take this dood! Huh doood!!! HUH DOOOOD!?!? DOOD HUH!!!!!! DOOOOOOOOOOOOOOOOOOOOOOOOOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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#7 2007-02-22 11:03:55

Zhylliolom
Real Member
Registered: 2005-09-05
Posts: 412

Re: Deleted

I'd like to note that "Problem 1" on your website, although very slightly different than my statement, was introduced to Delta by me, which in turn was presented to me by a colleague. I just thought I'd tell you this since you state that you "feel obliged to ask" before posting problems.

Here is the thread:

http://www.mathsisfun.com/forum/viewtopic.php?id=5833

Also, if you haven't solved it yet, you probably never will unless in a hallucinogenic state or if intense insight strikes. I only know one other person who has solved it.

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#8 2007-02-22 11:12:12

Sekky
Member
Registered: 2007-01-12
Posts: 181

Re: Deleted

Zhylliolom wrote:

I'd like to note that "Problem 1" on your website, although very slightly different than my statement, was introduced to Delta by me, which in turn was presented to me by a colleague. I just thought I'd tell you this since you state that you "feel obliged to ask" before posting problems.

Here is the thread:

http://www.mathsisfun.com/forum/viewtopic.php?id=5833

Also, if you haven't solved it yet, you probably never will unless in a hallucinogenic state or if intense insight strikes. I only know one other person who has solved it.

Well the comment I wrote underneath the problem sums up my theory, the function can't possibly be functional, although we could limit it.

Myself and a friend came up with the idea of having a ring whose set was the set of all functions, and whereby function composition was the additive operation (with an automorphic identity, obviously), such that IF we could prove that the group under addition contained an idempotent element (or that we could form a cyclic subgroup) we could find an element such that g is equal to its own inverse, so the problem is finding a monoid operation that distributes over function composition, which isn't easy.

I'd like to see a proof.

Last edited by Sekky (2024-06-24 08:15:30)

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#9 2007-02-22 11:59:35

Zach
Member
Registered: 2005-03-23
Posts: 2,075

Re: Deleted

...

Not really...

Firstly, his original attempt at retorting was completely terrible and improper, so I had to change that. I, however, wrote it out more subtly.

How that means I "got told" is beyond me.


Boy let me tell you what:
I bet you didn't know it, but I'm a fiddle player too.
And if you'd care to take a dare, I'll make a bet with you.

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#10 2007-02-22 13:28:11

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Deleted

Don't let Zach give you that impression. We're generally a nice, likable bunch of wonderful people. Zach's fine as well once you get to know him, he just sometimes gives people bad first impressions.


Why did the vector cross the road?
It wanted to be normal.

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#11 2007-02-22 15:50:25

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,713

Re: Deleted

It certainly is not hostile. There is enough hostility in the world, we don't need it here. We tend to just moderate bad stuff out.

You are very welcome here.


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#12 2007-02-22 16:15:47

Jai Ganesh
Administrator
Registered: 2005-06-28
Posts: 48,395

Re: Deleted

Hi Sekky,
Its nice to have you as a member in this forum!
A big (although belated) Welcome!!!


It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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#13 2007-02-22 17:31:58

Toast
Real Member
Registered: 2006-10-08
Posts: 1,321

Re: Deleted

Welcome Sekky!!! big_smile

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#14 2007-02-22 18:06:27

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,713

Re: Deleted

Sekky wrote:

Thanks! So you're a flash user?

I use a product called SwishMax to make Flash (coz I like it's interface better). But it can't do AS3 sad

Interestingly I have recently improved my  Complex Number Calculator

I found the hardest part was (and still is) parsing the user input.


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#15 2007-02-22 18:39:28

luca-deltodesco
Member
Registered: 2006-05-05
Posts: 1,470

Re: Deleted

MathsIsFun wrote:

I found the hardest part was (and still is) parsing the user input.

when i made my calculator couple of years ago, i can remember that about 400 lines of code was simply to figure out what the user had put into it, then another 400 odd lines parsing all possible syntax errors, and then another 400 odd lines of code splitting everything into an ordered set of operations on the memory that could then actually be run through to get the answer, and to plot the appropriate graph


The Beginning Of All Things To End.
The End Of All Things To Come.

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#16 2007-02-22 19:47:16

Zhylliolom
Real Member
Registered: 2005-09-05
Posts: 412

Re: Deleted

Sekky wrote:

...a ring whose set was the set of all functions, and whereby function composition was the additive operation...

In a ring (R, +, ·), (R, +) is an Abelian group. However, function composition is in general not commutative. (Even if (R, +, ·) were a semiring, (R, +) would be a commutative monoid; we cannot escape the commutativity.)

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#17 2007-02-22 19:59:58

Sekky
Member
Registered: 2007-01-12
Posts: 181

Re: Deleted

Zhylliolom wrote:
Sekky wrote:

...a ring whose set was the set of all functions, and whereby function composition was the additive operation...

In a ring (R, +, ·), (R, +) is an Abelian group. However, function composition is in general not commutative. (Even if (R, +, ·) were a semiring, (R, +) would be a commutative monoid; we cannot escape the commutativity.)

Oh yeah, (R,+) is Abelian....my mistake

So we try it in reverse, make function composition the multiplicative operation and find something over which is distributes, which is never going to happen.

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#18 2007-02-24 02:20:06

soha
Real Member
Registered: 2006-07-07
Posts: 2,530

Re: Deleted

Hi ,sekky
welcome to this great forum.


"Let us realize that: the privilege to work is a gift, the power to work is a blessing, the love of work is success!" smile smile
- David O. McKay

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#19 2007-02-24 02:50:58

power man
Member
Registered: 2006-12-26
Posts: 160

Re: Deleted

hi


I hate people who hate people.
most people make mistakes, butt not me! smile smile
why     is     it     when     you     are     writing     something     important     you     run     out       of        spa

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#20 2007-03-10 02:31:44

Stanley_Marsh
Member
Registered: 2006-12-13
Posts: 345

Re: Deleted

Hi , Dan .  I am simply just an ameteur , and you are professional , you learn a lot , hope I got the time too lol~~


Numbers are the essence of the Universe

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