Math Is Fun Forum

MathsIsFun

Administrator

Registered: 2005-01-21

Posts: 7,713

Logarithm Formulas

Logarithm Formulas

---

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

Jai Ganesh

Administrator

Registered: 2005-06-28

Posts: 48,402

Re: Logarithm Formulas

If

then

because

---

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Ricky

Moderator

Registered: 2005-12-04

Posts: 3,791

Re: Logarithm Formulas

Last edited by Ricky (2006-04-04 04:11:44)

---

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

Zhylliolom

Real Member

Registered: 2005-09-05

Posts: 412

Re: Logarithm Formulas

Logarithm of a Complex Number

where k is an integer.

Devantè

Real Member

Registered: 2006-07-14

Posts: 6,400

Re: Logarithm Formulas

(which is log(xy) = log x + log y)

Last edited by Devanté (2006-08-05 19:10:52)

Devantè

Real Member

Registered: 2006-07-14

Posts: 6,400

Re: Logarithm Formulas

Last edited by Devanté (2006-10-06 23:23:57)

Devantè

Real Member

Registered: 2006-07-14

Posts: 6,400

Re: Logarithm Formulas

random_fruit

Member

Registered: 2008-12-25

Posts: 39

Re: Logarithm Formulas

Can anyone explain Devante's post #7?  He says

This does not make sense to me, and seems to me to have exactly one value of x for which it is true.

Shekhar

Member

Registered: 2009-04-19

Posts: 1

Re: Logarithm Formulas

Can anyone prove the following....
Given,
((2/3)^k)n = 1
Required to prove,
k is equal to log of n on base 3/2

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Logarithm Formulas

Hi random_fruit;

It could be a quiz problem and I agree it appears  to have only 1 solution in R.

Last edited by bobbym (2009-04-19 19:44:38)

---

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

noobard

Member

Registered: 2009-06-07

Posts: 28

Re: Logarithm Formulas

If

then

because

hey ganesh jus a little thing
if we take  A and B of the same signs

here it should be

..

and in the other ones also... the argument has to be alwys positive

---

Everything that has a begining has an EnD!!!

sekhar5955

Member

Registered: 2009-11-25

Posts: 1

Re: Logarithm Formulas

Hi Shekhar,
Here is the solution.
   ((2/3)^k)n = 1
⇒(2/3)^k = 1/n
⇒(2/3)^k = n-¹
Applying log on both sides.
⇒k log(2/3) = -log n
Multiplying (-) on both sides
⇒k log(2/3)-¹ = log n
⇒k log(3/2) = log n
∴ k = (log n)/(log (3/2))
⇒ k = log n base (3/2) 

Can anyone prove the following....
Given,
((2/3)^k)n = 1
Required to prove,
k is equal to log of n on base 3/2