What do you think?

bobbym · 2010-05-03 19:28:18

Hi;

I am not seeing it that way. With your assumption that their is no cost 13 is the max but with the assumption that the price they charge is the cost ( or penalty ) then it is not. That is what the question implies according to B: B's reasoning is correct based on that assumption.

P(1) = 75 sold and 3 unsold which has a cost of -3. Profit 72

P(2) = 72 sold and 6 unsold which has a cost of -12 Profit 132

P(3) = 69 sold and 9 unsold which has a cost of - 27 Profit 180

The negative numbers are where the 3x^2 comes from.

ZHero · 2010-05-03 19:44:47

Hey... bobbym!!!

bobbym wrote:

... the price they charge is the cost ( or penalty ) then ...

yeah.. that can be a case!! but it sounds ridiculous!

bobbym wrote:

... P(3) = 69 sold ...

bobbym · 2010-05-03 19:47:08

Hi;

I am in full agreement there, I think B is ridiculous also.

ZHero · 2010-05-03 20:07:31

yeah.. last night i thought for more than an hour over the problem figuring out the difference between A's and B's statements.
humorously enough, its similar to tha phrontister's "extra $2 and the missing $" problem!

bobbym · 2010-05-04 10:15:14

Tough:

Prob 48

n people check their scarf and coat in at a large restaurant, each receives a slip. The slips are misplaced and the attendant is forced to randomly choose which scarf and coat to give each person. What is the probability as n approaches infinity that no one gets either a scarf or a coat that is his?

A) says P = 1.
B) says 1 / (2 e )
C) says 1 / e
D) says 1 / e^2
E) says 0

What do you think?

bobbym · 2010-05-06 22:12:02

A real dilly!

Prob 49

A sequence follows the pattern of.

1,3,1,3,3,1,3,3,3,1,3,3,3,3,1,3,3,3,3,3,1....

First two terms sum to 4. First 8 terms sum to 18. What does the 10001 term sum to?

bobbym · 2010-05-08 03:08:15

Easy one:

Prob 50

If:

mathsyperson · 2010-05-08 03:18:40

ZHero · 2010-05-08 04:45:23

bobbym · 2010-05-08 05:49:21

That answer is correct I believe! Good work.

phrontister · 2010-05-09 07:04:48

Hi Bobby,

Last edited by phrontister (2010-05-10 09:27:23)

bobbym · 2010-05-09 07:12:13

Hi phrontister;

That is correct. Interesting solution, one that I din't know.

phrontister · 2010-05-09 12:51:40

Hi Bobby,

I found that my 13133... sequence formula gives an incorrect answer for the last element of each segment.

I've corrected it, and I think that it now works for all cases.

bobbym · 2010-05-09 12:59:57

Hi;

But you got the right answer, it must not have affected the calculation.

phrontister · 2010-05-09 13:13:54

No, it didn't. For some reason the sum at the end of each segment was 2 less than what it should have been. All the others - the intermediates and the first element of segments - were fine.

Adapting the formula that solves for n was my undoing.

Last edited by phrontister (2010-05-09 13:28:29)

bobbym · 2010-05-09 14:06:57

Anybody, want to see my solution?

phrontister · 2010-05-09 14:18:00

Yes, please! I'm very interested to see it.

bobbym · 2010-05-09 14:57:59

Hi phrontister;

Calm down my friend, remember your arteries. I will post it right here.

phrontister · 2010-05-09 22:23:29

bobbym wrote:

Calm down my friend, remember your arteries.

Is that a problem for a 27-year-old? My ticker's motoring along well and my blood pressure's normal.

That bus will probably get me, though; or (and this is MIF's fault) sleep-deprivation-induced organ malfunction.

Not that I'm very clever on the keyboard...here's my best effort, which I recorded while trying out some buttons on a synth I had. If you have the stamina and determination to hear it right through to the end you'll hear quite a range of instruments and effects. You may also think that I recorded it on a windy day with the door open...but I didn't.

bobbym · 2010-05-09 22:30:12

Hi phrontister;

Wunderbar! It made me start dancing.

phrontister · 2010-05-09 22:43:40

Publish your performance on YouTube. Some greats started that way.

Maybe not with dancing, though...although you could break new ground. That is, if you don't fall over!

Last edited by phrontister (2010-05-09 22:45:46)

bobbym · 2010-05-09 22:46:20

I do have an upcoming vid for youtube. It will answer many questions. I will say no more.

phrontister · 2010-05-09 22:48:16

I'll try to think up some questions before I see the production.

bobbym · 2010-05-09 22:51:49

Unfortunately or fortunately, these are not questions that you are asking. Or are likely to be asking in the near future.

These are questions being asked by other members about me.

bobbym · 2010-05-10 04:35:26

Here is my solution to the sequence problem:

Math Is Fun Forum

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