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in the diagram of triangle ABC and EDC below, AE and BD intersect at C, and angle
CAB approx= CED
which method can be used to show that triangle ABC must be similar to Triangle EDC.
1. SAS
2.SSS
3.AA
4.HL
please explain? thanks
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∠ACB=∠ECD
∠CAB=∠CED
Hence, the third angles must also be equal...
∠ABC=∠EDC
∴ AAA or (AA)
If two or more thoughts intersect, there has to be a point!
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