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#1 2010-06-24 17:04:54
- lakeheadca
- Member
- Registered: 2010-01-31
- Posts: 37
Problem#3 Grade 11 Geometry
What Is The Length Of Ad To The Nearest Tenth Of A Centimeter?
1)3.6
2)6.0
3)6.4
4)4.0
Please Explain. Thank You.
Last edited by lakeheadca (2010-06-24 17:12:40)
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#2 2010-06-24 17:17:51
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Problem#3 Grade 11 Geometry
Hi lakeheadca;
Did you try to form your equations like this:
a^2 + x^2 = 6^2
a^2 + (10-x)^2 = 8^2
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#3 2010-06-24 17:20:21
- lakeheadca
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- Registered: 2010-01-31
- Posts: 37
Re: Problem#3 Grade 11 Geometry
6²+8²=c²
100=c²
10=c
10x=6²
X=3.6 Ans.
But Why 10x Multiplying With X???
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#4 2010-06-24 17:25:14
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Problem#3 Grade 11 Geometry
That is correct,x = 3.6. I don't understand where you do not understand.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#5 2010-06-24 17:28:40
- ZHero
- Real Member
- Registered: 2008-06-08
- Posts: 1,889
Re: Problem#3 Grade 11 Geometry
ADC∼CDB
AD/AC = CD/CB
x/6 = √(6² - x²)/8
Solve for 'x'
If two or more thoughts intersect, there has to be a point!
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#6 2010-06-24 17:30:34
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Problem#3 Grade 11 Geometry
You can subtract the top equation from the bottom one to get:
h^2 + x^2 = 6^2
h^2 + (10-x)^2 = 8^2 The h^2 will cancel when you subtract.
(10-x)^2 - x^2 = 8^2 - 6^2
100 - 20 x = 28
-20 x = -72
20 x = 72
x = 3.6
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#7 2010-06-29 03:29:09
- lakeheadca
- Member
- Registered: 2010-01-31
- Posts: 37
Re: Problem#3 Grade 11 Geometry
ZHERO:
ADC∼CDB (One triangle looks bigger than other one????) they don't looks equal. Are you saying something about ratio
Bobby:
what is a² and what is h²
if (10-x) is AD
so DB should be 10+x or the same 10-x ???
lost again. hate Pythagorean.
Last edited by lakeheadca (2010-06-29 03:30:53)
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#8 2010-06-29 03:34:47
- lakeheadca
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- Registered: 2010-01-31
- Posts: 37
Re: Problem#3 Grade 11 Geometry
I think first time you guys came across someone who is that bad in Math
Last edited by lakeheadca (2010-06-29 03:42:35)
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#9 2010-06-29 03:58:24
- ZHero
- Real Member
- Registered: 2008-06-08
- Posts: 1,889
Re: Problem#3 Grade 11 Geometry
Yea.. The triangles are "similar" and not "congruent".
Its means that all their angles are equal and their sides are "proportional".
If two or more thoughts intersect, there has to be a point!
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#10 2010-06-29 09:44:15
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Problem#3 Grade 11 Geometry
I think first time you guys came across someone who is that bad in Math
Calm down, I am worse. If I appear better, it is only because I have been doing it longer.
You might be getting a little confused over the fact we are using 2 different methods. Don't be. Just means you have a choice of what you like and understand best. Right now you are in school, your teachers are jamming many methods down your throat. They want you to learn all of them. When you are on your own you will get to choose what you like and are good at. I like simultaneous equations and solve many problems with them.
Bobby:
what is a² and what is h²
if (10-x) is AD
so DB should be 10+x or the same 10-x ???
No, If AB = 10 and AD = x then DB = 10 - x
a is side CD so I will out it into easier notation, sorry about the confusion.
1) (CD)^2 + x^2 = 6^2 Triangle CDA
2) (CD)^2 + (10-x)^2 = 8^2 Triangle BDC
Again 2 equations and 2 unknowns. If you subtract eqtn. 1 from eqtn 2 you will eliminate (CD)^2.
Can you now solve for x?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#11 2010-06-30 14:15:13
- lindsey8555
- Member
- Registered: 2010-06-07
- Posts: 4
Re: Problem#3 Grade 11 Geometry
Archimedes run rings around your head? Well you've come to the right place. This is where you'll find almost everything you'll ever need to know about Geometry. We have a special page on constructions and plenty of sample problems to help you understand the concepts. Have a blast and don't forget to check out our Glossary - it's huge!
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#12 2010-06-30 15:31:01
- lakeheadca
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- Registered: 2010-01-31
- Posts: 37
Re: Problem#3 Grade 11 Geometry
Thank you Bobby. I got it. You made the problem easy.
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#13 2010-06-30 19:04:15
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Problem#3 Grade 11 Geometry
Your Welcome!
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#14 2010-08-11 18:45:34
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Problem#3 Grade 11 Geometry
Hello allanmc0719
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#15 2010-08-11 21:38:17
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Problem#3 Grade 11 Geometry
Hi allanmc0719;
Sorry to hear that, hope you feel better.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#16 2010-08-12 12:30:40
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Problem#3 Grade 11 Geometry
No, not me. I hate resting. But if you must then...
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
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