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Exclusive of the numbers 1 and 1176, how many factors are there for the number 1176.
a.20
b. 22
c.24
d. 26
is there any trick to solve?
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In general...
If a number N has prime factorization as follows...
N=a[sup]p[/sup]×b[sup]q[/sup]×c[sup]r[/sup]...
Then the number of distinct factors, including 1 and N is given by...
Number of Factors = (p+1)(q+1)(r+1)...
Here, 1176 = 2[sup]3[/sup]×3[sup]1[/sup]×7[sup]2[/sup]
∴ Number of factors = (3+1)(1+1)(2+1) = 24
If two or more thoughts intersect, there has to be a point!
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