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ABCD is a square with area 9. efgc is a square in which EC=1/3(BC). HIJC is s square in which HC=1/3(EC). If this pattern is continued so that there are a total of ten squares with common vertex at C. and in which each square lies inside its predecessor, what is the area of the tenth square?
Answer: 9^-8
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Hi lakeheadca;
That answer is correct.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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how to solve this problem. please explain!
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ABCD has area 3 x 3 = 9 = 9 ^ 1
EFCG has area 1 x 1 = 1 = 9 ^ 0
HICJ has area 1/3 x 1/3 = 1/9 = 9 ^ -1
KLCM has area 1/9 x 1/9 = 1/81 = 9 ^ -2
..... .... .....
10th square has area 3^ -8 x 3 ^ -8 = 9 ^ -8
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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