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This is pretty neat.
DON'T CHEAT BY SCROLLING DOWN FIRST!
It takes less than a minute. Work this out as you read. Be sure you don't read the bottom until you've worked it out! This is not one of those waste of time things, it's fun.
1. First of all, pick the number of times a week that you would like to have chocolate (more than once but less than 10)
2. Multiply this number by 2 (just to be bold)
3. Add 6
4. Multiply it by 50 -- I'll wait while you get the calculator
5. If you have already had your birthday this year add 1759 .. If you haven't, add 1758.
6. Now subtract the four digit year that you were born.
You should have a three or four digit number The first digit of this was your original number (i.e., how many times you want to have chocolate each week). The next two numbers are YOUR AGE! THIS IS THE ONLY YEAR (2010) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS.
For more, Check out http://coolemailforwards.com/tags-Math.php
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Hi priya143;
Welcome to the forum!
n = 7;
2n = 14
14+6 = 20
50*20 = 1000
1000 + 1759 = 2759
2759 - 1980 = 779
The 7 is correct but I am not 79!!!!!
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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This sure didn't work out for me. I said 7 times a week for chocolate, multiplied by 2 to get 14. I added 6 to equal 20. I multiplied by 50 to get 1,000. I added 1758 to get 2758 and subtracted 1951. I got 807 - not of which is correct (in terms of chocolate wanted or certainly my age). What gives?
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Hi all;
There are a number of errors in the problem.
Step 3) should be add 5 not add 6
And this riddle only works for the year 2009, not 2010.
Let's say I was born in 1980.
n = 7
2n = 14
n+5 = 19
50 * 19 = 950
950 + 1759 = 2709
2709 - 1980 = 729
7 is the chocolate and yes I was 29 in 2009
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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