Math Is Fun Forum

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Find an equation showing special graph

Is it a turkey?

---

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

Sumasoltin

Member

Registered: 2012-04-28

Posts: 30

Re: Find an equation showing special graph

Aha! I learnt an American created the"Batman equation" in China.Did you hear about anything about it?

anonimnystefy

Real Member

From: Harlan's World

Registered: 2011-05-23

Posts: 16,049

Re: Find an equation showing special graph

It's mayo! Or mustard?

---

“Here lies the reader who will never open this book. He is forever dead.
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.

Sumasoltin

Member

Registered: 2012-04-28

Posts: 30

Re: Find an equation showing special graph

A leg of turkey exactly!

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Find an equation showing special graph

The Batman equation?

---

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

Sumasoltin

Member

Registered: 2012-04-28

Posts: 30

Re: Find an equation showing special graph

See it here:w w w.howtogeek.com/106221/stupid-geek-tricks-how-to-plot-the-batman-curve-in-google-search/
Well , math is a subject created by God, and you can make any thing into equations if you want. Pencils, flowers, waves, boats, mountains, bra and math(:P),and even a girl !

Last edited by Sumasoltin (2012-04-30 01:49:00)

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Find an equation showing special graph

I got it, thanks for the info.

---

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

benice

Member

Registered: 2010-06-10

Posts: 117

Website

Re: Find an equation showing special graph

The Batman equation?

Hi bobbym,

The original post is here: http://redd.it/j2qjc.

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Find an equation showing special graph

Hi benice;

Thanks for coming over. Thanks for the link too.

---

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

Sumasoltin

Member

Registered: 2012-04-28

Posts: 30

Re: Find an equation showing special graph

The Batman equation?

Hi bobbym,

The original post is here.

Hi,benice;
I review the sites and infer that the earliest one is before 2011-07-29 09:35:26 (+8). But the site you gave just show "9 months ago", when the equation was flooding, so I don't know whether that is the original one.
We tried to plot it, only to found it abused "sqrt" so there is no plot. I tried to correct but gave up later because of the complex numbers (complex, not "i").

Last edited by Sumasoltin (2012-05-02 12:07:33)

benice

Member

Registered: 2010-06-10

Posts: 117

Website

Re: Find an equation showing special graph

Hi,benice;
I review the sites and infer that the earliest one is before 2011-07-29 09:35:26 (+8). But the site you gave just show "9 months ago", when the equation was flooding, so I don't know whether that is the original one.

The original post was submitted on 28 Jul 2011. (Look at the upper right corner of the comment page.)

We tried to plot it, only to found it abused "sqrt" so there is no plot. I tried to correct but gave up later because of the complex numbers (complex, not "i").

Plot each component separately:
f1(x,y) = ((x/7)^2) * sqrt( sign(abs(x)-3) ) + ((y/3)^2) * sqrt( sign(y+3*sqrt(33)/7) ) - 1
f2(x,y) = abs(x/2) - ((3*sqrt(33)-7)/112)*(x^2) - 3 + sqrt(1 - (abs(abs(x)-2)-1)^2) - y
f3(x,y) = 9*sqrt( sign((1-abs(x))*(abs(x)-0.75)) ) - 8*abs(x) - y
f4(x,y) = 3*abs(x) + 0.75*sqrt( sign((0.75-abs(x))*(abs(x)-0.5)) ) - y
f5(x,y) = 2.25*sqrt( sign((0.5-abs(x))*(abs(x)+0.5)) ) - y
f6(x,y) = 6*sqrt(10)/7 + (1.5-0.5*abs(x))*sqrt(sign(abs(x)-1)) - 6*(sqrt(10)/14)*sqrt(4-(abs(x)-1)^2) - y