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Given a random variable X with probability density f(x) = x/8 for 0 ≤ x ≤ 4:
1) What is the probability that X is between 1 and 3?
2) Find the expected value of X
How do you find the expected value for these type of questions? In general to find the expected value you use (x*(p(x)), so does that mean you have to plug in numbers 0 to 4 and apply the same formula after? Also for number 1 I got 1/2 as an answer.
Last edited by genericname (2012-10-20 11:04:07)
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Hi;
I am getting that for 1 also, for 2) I am getting 8 / 3.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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What is the formula for getting 8/3?
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I did it this way:
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I'm not quite understanding it. The value of x = 0, 1, 2, 3, 4?
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Nope, the value of x is those and everything in between them. This is a continuous function.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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How does it come up to 8/3? (Sorry for the dumb questions)
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Hi;
Did you see post #4? That is the formula. I just took the endpoints from the problem.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Ah, thank you. I was overthinking it.
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Hi;
Or maybe I am underthinking it. Anyway, hope that helps a little.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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