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On this question:
"Why do you think this is ?"
you answered:
"The third row uses the trapezium rule to calculate (approximately) the area of each section".
"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"
Thomas Ioannes Stiltes. ... I made it!
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I will try again.
Please choose the following
base radius of cone
height of cone
number of slices
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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"number of slices"
While you will have trapezes result will be approximate. As soon as you will take two areas of a circle
Bob
Try to translate by means of the dictionary start top from Russian. I here all accurately wrote all. I feel that my robot doesn't translate all sense of that that I want to inform you.
http://bolshoyforum.org/forum/index.php?topic=297286.0
I will try to explain a bean to you so. Present that on the plane there is circumference of any radius. ANY (! ! ! ) It is the line, it - not the area (! ! ! ) Now you to it add one more circumference in the same plane. Either it is more or has no value but such that between these two circumferences it was impossible to insert one more less.
It already area, instead of line. Elementary Square, the most smaller also is differential of the area of a circle. Any more line. But already area! It also is:
The sum of elementary segments of line (pieces) lying in one direction (not in parallel):
- is a line.
One point - One point it yet length not segment of line. Three points - not elementary. Integration is an absolute measure it doesn't depend on a unit of measure which the person can choose randomly.
You understand this?
P.S. I try to translate twice: from Russian into English then from English into Russian - sense is not adequate. I don't know what to do.
Last edited by 21122012 (2013-01-07 15:11:57)
"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"
Thomas Ioannes Stiltes. ... I made it!
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<structural analysis> is true => <cone test is good>
So please do not give up on the test.
I will use upper and lower bounds.
sense is not adequate
I agree. Translation is one word at a time. Phrases are not translated properly. If a word has two meanings, translation may pick the wrong one.
Suggestion:
Give Russian and English. Stefy may help with meanings.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Give me the test.
"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"
Thomas Ioannes Stiltes. ... I made it!
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Please choose the following
base radius of cone
height of cone
number of slices
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Please choose the following
base radius of cone
height of cone
number of slicesBob
Didn't understand. You look post #28 the most top line.
"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"
Thomas Ioannes Stiltes. ... I made it!
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I have made a new spreadsheet.
I have used R = 34
H = 17
number of slices = 17
Row 4 shows the r values from 0 to 34
Row 5 shows the h values from 0 to 17
Row 6 calculates the volume using
eg. The G column formula is =1/3*PI()*G4^2*G5
Row 7 calculates values of pi r^2. The formula for the G column is =PI()*G4^2
Row 9 calculates the area of a rectangle below the curve.
This is the yellow area shown in my second diagram. The formula in the G column is =G7*(H4-G4)
Row 10 sums these values. Formula in the G column is =SUM($B$9:G9)
Row 11 calculates the area of a rectangle above the curve.
This is the sum of the yellow and green areas in my diagram. The formula in the G column is =H7*(H4-G4)
Row 12 sums these values. Formula in the G column is =SUM($B$11:G11)
Row 10 gives the lower bound for the area under the curve. 44861
Row 12 gives the upper bound for the area under the curve. 53005
Therefore 44861 < area under curve < 53005
The correct volume of the cone is 20579
Conclusion: the following formula is NOT correct.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Bob!
You don't understand that such differential. It not SMALL INCREMENT. This ELEMENTARY INCREMENT! And you use the SMALL INCREMENT.
You didn't read post #28. Read, I there show a difference. But I now will repeat in relation to your example. You have the circle area. Not important what radius. Understand, radius length yet has no value! This area of a circle - the area, but not volume! This is element of Planimetrics, but not element of Solid Geometry. You understend me? This element of Planimetrics has its radius?
Now take the radius one point smaller or one point more and construct the circle area. Put from above on the first circle. Look at thickness sideways. It will be elementary volume of
In what difference between
and
Which in the first case creates volume a cone, and in the second case creates cylinder volume???!!!
Everything is concluded in a difference of these two expressions:
prompts that at distance from top circle will settle down. prompts that at any distance from top IDENTICAL circles: will settle down.You understand?
P.S.
In everything the limit which uses Calculus is guilty.
Because this limit it is possible to give only presentation of VALUE of the DERIVATIVE but not the most derivative.
In Structural Analysis the absolute limit on accuracy for receiving derivative function instead of its value is used:
Last edited by 21122012 (2013-01-09 14:47:49)
"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"
Thomas Ioannes Stiltes. ... I made it!
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I do not understand why you use calculus at all in your structural analysis.
You claim it has errors and then use it anyway.
I have read post 28.
Integral calculus is built upon small increments. If you won't accept that then I suggest you remove all references to calculus from your theory and present it properly.
I do not understand the term elementary increment. I think your translation robot has failed to give you the correct English.
I have already tried to explain to you why
fails to give you the correct result. Of course you get the volume of a cylinder if you treat pi r squared as a constant. Most mathematicians know you have to change the 'r' term to a function of 'h' before you integrate.
I see no point in continuing until you clear up what you are trying to do in post 22.
Now I look at post 22 again I see that your integration for a cylinder is wrong too.
Please use the upper bound / lower bound method to justify these or change them.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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I translate from English. I can't understand that you want. What mine have to be actions?
"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"
Thomas Ioannes Stiltes. ... I made it!
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hi 21122012
Here you say
How can this be from o to r ? The variable is h.
Note:
And you say
Note:
This is my last word on integration.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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That is not correct. You cannot have h both in the integration limits and as the variable which you are integrating with respect to...
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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Hi anonimnystefy;
That is not correct. You cannot have h both in the integration limits and as the variable which you are integrating with respect to...
Of course you can.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Then you could have something like
...Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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Hi;
Take these over to alpha.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Alpha understand it differently then they should be understood. It looks at the two k's (and x's) as different, while they are in fact the same k (x)...
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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No, they are not the same, in the integral you do not substitute for the x in the dx. The index of summation obviously is the same.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym
All instances of a variable name in a single expression represent a single variable, so the three x's and k's are the same...
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
Offline
One thing at a time.
I do not see any reason why this
is not allowed.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hi 21122012
Here you say
How can this be from o to r ? The variable is h.
Hi bob!
WOW!!!!!!!!
Look this:
It is a special case of a general view:
Note:
It is a special case. You choose only one option from all possible options of height. Such, when height равнв to basis radius. I didn't think that it is difficult for understanding.
And you say
I couldn't say such nonsense. It not cone volume, because it cylinder volume.
Note:
This is my last word on integration.
Bob
You don't understand difference of a variable from value of a variable which is constants.
If you took two independent
variables, then made their dependent
Then took values of these dependent variables
these values can't become independent variables
It is absurdity!
Function of a type:
in a geometrical form of a mnterpretation where - x radius, y - height can be constructed only in the form of cylinder volume.
The volume of cone can be constructed only if
Last edited by 21122012 (2013-01-11 13:08:41)
"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"
Thomas Ioannes Stiltes. ... I made it!
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bob bundy wrote:That is not correct. You cannot have h both in the integration limits and as the variable which you are integrating with respect to...
This isn't an error. It is an unnecessary duplicator of a variable of a mntegrirovaniye. In the main theorem of calculation it is a case when the variable doesn't lie in an interval and is the interval end.
Last edited by 21122012 (2013-01-11 17:56:29)
"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"
Thomas Ioannes Stiltes. ... I made it!
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hi 21122012,
A demonstration that 2 variables may be independently chosen and yet, still be related.
You don't understand difference of a variable from value of a variable which is constants.
If you took two independent variables, then made their dependent
Then took values of these dependent variables these values can't become independent variables
There are many formulas with three variables which will allow you to choose two variables 'independently'. The three are still related.
example 1
You may choose D = 24 Km, and S = 4 Km/hr. This was a free and independent choice for D and S. But they are still related by the formula.
example 2
is the equation for a circle, centred on (0,0)
You may choose any values for x and y because any point will lie on some circle.
But x and y are related.
example 3
Once again you may choose u and t independently but the formula still holds.
Why are you so reluctant to accept that, for a cone, there is a formula connecting r and h?
If r is fixed, then it is not a cone is it?
r has to vary as h varies to make a cone.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hy bob
You forgot about what we speak. More true you forgot that moment because of which our dialogue began. Therefore you displaced sense in other party. I will remind you and you will see that you lost the conversation reason.
"....I will show one real mistake. But usually after such my subjects in Russia deleted at once. I will try here. We look the link:
http://en.wikipedia.org/wiki/Partial_derivative
We see a formula of a full derivative of volume of a cone on height:
We integrate this derivative and we receive... cylinder volume:
...."You remembered why we started talking about a cone and the cylinder? Therefore when we tell about volumes of these two geometrical figures that I always I speak about them and I remember the reason for which we speak about it. And you tell everything that doesn't treat at all a subject of our dispute. You didn't prove to me that a formula
it is cone volume. And still didn't give integral for calculation of volume of the cylinder which would differ from this formula THOUGH SOMETHING!
Last edited by 21122012 (2013-01-12 08:10:17)
"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"
Thomas Ioannes Stiltes. ... I made it!
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You didn't prove to me that a formula
it is cone volume.
Yes I did. But it is so clear in my head I will do it again.
Obviously h = r = 0 gives C = 0
So
The reason you get the formula for a cylinder is because you insist on saying pi r^2 is constant.
Of course it isn't for a cone, but it is for a cylinder.
Note: This work has nothing to do with partial derivatives. As r and h are related it is possible to avoid any parrtial derivatives at all simply be using the relationship between r and h.
If you will not accept this, then we might as well cease communicating.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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