What do you think?

gAr · 2013-02-16 23:41:02

I experimented with mean and mode to get approximate values.
Can we numerically solve the simultaneous equations?

bobbym · 2013-02-16 23:46:02

Hi gAr;

I am sorry, but on this one Mr anonimnystefy has left me dumber than a burned out stump. Apparently his method has fried my brain. I am so confused I can not solve 3 + x = 9. Can you show me what you want done? You can use codecogs for the latexing.

gAr · 2013-02-17 00:05:39

Hi bobbym,

Don't worry!
I was trying to solve for the mode and mean:
l*(1-1/k)^(1/k) = 7
l*gamma(1+1/k) = 4084571/559872

bobbym · 2013-02-17 00:08:37

Hi;

Only those two equations?

anonimnystefy · 2013-02-17 00:22:04

bobbym wrote:

When you do 4 of a kind, do you use the 6th row instead of the 5th row of the T's?

Hi bobbym

No, when I do 4, the numbers are in that table!

bobbym · 2013-02-17 00:23:27

No, when I do 4, the numbers are in that table!

Where are they? That is what I would like to know.

anonimnystefy · 2013-02-17 00:25:35

I don't know if they are even in the OEIS.

bobbym · 2013-02-17 00:27:27

So you are saying they are not?

gAr · 2013-02-17 00:29:30

Hi bobbym,

Yes.

bobbym · 2013-02-17 00:30:56

I have:

as one set of roots.

Last edited by bobbym (2013-02-17 00:31:12)

anonimnystefy · 2013-02-17 00:31:18

I just checked. They are not in the OEIS.

bobbym · 2013-02-17 00:33:55

Then I will work with your coefficient idea.

anonimnystefy · 2013-02-17 00:37:04

Coefficient idea?

bobbym · 2013-02-17 00:39:33

Your gf idea, the terms on the right of your sum.

anonimnystefy · 2013-02-17 00:42:44

Ah! Okay.

gAr · 2013-02-17 00:43:16

whoops, did not fit as I expected.
Taking a break from this, see you guys later.

anonimnystefy · 2013-02-17 00:44:56

Hi gAr

See you later!

Hi bobbym

I think the GF coefficients are Stirling numbers of the second kind!

bobbym · 2013-02-17 00:47:14

Hi;

Okay gAr come back soon.

Hi anonimnystefy;

I have not looked at that yet.

anonimnystefy · 2013-02-17 00:53:42

Hi bobbym

Sorry, no, those are not Stirling numbers. False alarm!

bobbym · 2013-02-17 00:59:30

To make sure I am doing this right. The notation of

[x^3]{1 + x + x^2 + 10x^3 + x^4}

returns 10, yes?

anonimnystefy · 2013-02-17 01:00:07

Yes.

bobbym · 2013-02-17 01:10:08

Okay, I have translated your maxima code into Mathematica code.

anonimnystefy · 2013-02-17 01:13:11

Great! Did you take the general formula function, or the special cases?

bobbym · 2013-02-17 01:17:30

Your general formula. I have it working.

anonimnystefy · 2013-02-17 01:29:52

Great!

Math Is Fun Forum

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