Math Is Fun Forum

burgess

Member

Registered: 2014-06-26

Posts: 49

Website

Help me with math puzzle

30 laborers, working 7 hours a day can finish a piece of work in 18 days. If the laborers work 6 hours a day, then what is the number of laborers required to finish the same piece of work in 30 days?

Thanks

Bob

Administrator

Registered: 2010-06-20

Posts: 10,619

Re: Help me with math puzzle

hi burgess

To do problems like this, vary one thing at a time.

If the number of days is held constant and you reduce the time from 7 to 6 hours, that will need more laborers (as they've got less time).  So multiply by 7/6.

If the number of days is now allowed to change from 18 to 30 days, that will need less laborers (they've got more days).  So multiply by 18/30.

So the number of laborers required will now be:

30 x 7/6 x 18/30 =

Alternatively, invent a unit to describe what has to be done.  Let's call it the person/hour/day unit.

To start with there are 30 x 7 x 18 person/hour/days of work to do.

But they work 6 hours in a day, so 30 x 7 x 18 divided by 6 person/days to complete the job.

But they have 30 days to do it, so (30 x 7 x 18)/6 divided by 30 people will be needed.

As you can see, it comes to the same calculation either way.

Hope that helps, 

Bob

ps.  More on this at http://www.mathsisfun.com/algebra/direc … ional.html

Last edited by Bob (2014-07-01 22:43:09)

---

Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob

burgess

Member

Registered: 2014-06-26

Posts: 49

Website

Re: Help me with math puzzle

Thank you much for explaining in detail!!!

hi burgess

To do problems like this, vary one thing at a time.

If the number of days is held constant and you reduce the time from 7 to 6 hours, that will need more laborers (as they've got less time).  So multiply by 7/6.

If the number of days is now allowed to change from 18 to 30 days, that will need less laborers (they've got more days).  So multiply by 18/30.

So the number of laborers required will now be:

30 x 7/6 x 18/30 =

Alternatively, invent a unit to describe what has to be done.  Let's call it the person/hour/day unit.

To start with there are 30 x 7 x 18 person/hour/days of work to do.

But they work 6 hours in a day, so 30 x 7 x 18 divided by 6 person/days to complete the job.

But they have 30 days to do it, so (30 x 7 x 18)/6 divided by 30 people will be needed.

As you can see, it comes to the same calculation either way.

Hope that helps, 

Bob

ps.  More on this at http://www.mathsisfun.com/algebra/direc … ional.html