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In this figure, mass M is fixed on the wall.How much force on mass m=5 kg should be applied so that it won't slip.
(given: acceleration of van=5m/s^2 ;coefficient of friction between m and M=0.4)
Pls help.
Last edited by niharika_kumar (2014-08-22 04:48:09)
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The reaction force between m and M is 5kg*5m/s^2
To balance the friction, you must give a force of 5kg*5m/s^2*0.4
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I thought the the same but it is an MCQ question with options as follows:-
a)170 N
b)180 N
c)150 N
d)250 N
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NB: The 150 N horizontal force consists of 25 N required to keep m stationary relative to the van and 125 N needed to generate the frictional force to balance its weight.
Last edited by Olinguito (2014-08-22 23:39:15)
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wow, you explained it so easily and well.(It reminded me of bob.)
thank you
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