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Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym,
The solution #5433 is correct. Good work!
#5434. Find the positive value of 'k' for which the equation
and have real roots.It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Hi bobbym,
#5435. The radius of a wheel is 0.25 meter. Find the number of revolutions its will make to travel a distance of 11 kilometers.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Hi bobbym,
The solution #5435 is correct. Neat work!
#5436. Difference between the circumference and radius of a circle is 37 centimeters. Find the area of the circle.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
Offline
Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Hi bobbym,
The solution #5436 is correct. Excellent!
#5437. If a wire is bent into the shape of a square, then its area is 81 square centimeters. When the same wire is bent into a semi-circular shape, then find the area of the semi-circle.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Only a friend tells you your face is dirty.
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Hi math9maniac,
# 5438. Find the area of a circle whose circumference is 22 centimeters.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Only a friend tells you your face is dirty.
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Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Hi math9maniac and bobbym,
The solution #5438 is correct. Neat work, math9maniac and bobbym!
#5439. Find the area of a quadrant of a circle whose circumference is 22 centimeters.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Mathaholic | 10th most active poster | Maker of the 350,000th post | Person | rrr's classmate
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Hi mathaholic,
#5440. The circumference of a circle exceeds the diameter by 16 centimeters. Find the radius of the circle.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Oh.
Mathaholic | 10th most active poster | Maker of the 350,000th post | Person | rrr's classmate
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Hi bobbym and mathaholic,
Excellent, bobbym!
#5441.The first term and the last term of an Arithmetic Progression 8 and 65 respectively. If the sum of all its terms is 730, find its common difference.
.
.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
Offline
Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Only a friend tells you your face is dirty.
Offline
Mathaholic | 10th most active poster | Maker of the 350,000th post | Person | rrr's classmate
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Hi bobbym, math9maniac, and mathaholic,
math9maniac : The solution #5439 is correct! Excellent!
bobbym and mathaholic : The solution #5441 is correct! Brilliant!
#5442. Points A (-1,y) and B (5,7) lie on the circle with center O (2,-3y). Find the values of 'y'.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
Offline
Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Hi bobbym,
Excellent!
#5443. Solve :
.It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
Offline
Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline