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**mctoosh0****Member**- Registered: 2021-05-26
- Posts: 1

a triangle is show with side lengths 3, 5 and 8. The length 8 is bisected and an unknown length x connects this midpoint and the vertex of the 2 other sides. The solution contends the unknown length is 1.

How can this be? Can you have a triangle if the total length of 2 sides is NOT longer than the 3rd? - No.

The solution must be x=0. intuition also says it must be zero.

Let's use algebra to solve. Construct a line from the vertex of lines 5 &3 perpendicular to the side length 8. call this unknown length b. The distance between the mid-point of the length 8 and the perpendicular line is unknown. call this length a.

using pythagoras. 1. b^2+(4-a)^2=3^2 & 2. b^2+(4+a)^2=5^2.

substitute b^2 from 1 into 2. Solve for 1. a=1

substitute a=1 and equations 1 & 2 give you b = 0. If b=0 then x=0

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**Bob****Administrator**- Registered: 2010-06-20
- Posts: 9,355

hi mctoosh0

Welcome to the forum.

That proof looks good to me. Well done!

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Sometimes I deliberately make mistakes, just to test you! …………….Bob

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