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**excelerator****Member**- Registered: 2022-10-12
- Posts: 1

(Apologies if this is some kind of a repost or the wrong place or whatever - I did search for a thread on it before I started a new topic.)

https://www.mathsisfun.com/puzzles/four-people-travel-solution.html

I thought this was funny - the way it is written

Four people are traveling to different places on different types of transport.

Their names are: Rachel, John, Mr. Jones and Cindy.

They either went on train, car, plane or ship.

• Mr. Jones hates flying

• Cindy has to rent her vehicle

• John gets seasick

How did they each travel?

It took me a few minutes but then I came up with ONE answer (not 3 as in the solution).

Cindy rented the car, obvs.

Then I stalled, I had Mr. Jones NOT plane and I had John NOT ship (I didn't know there could be 3 answers).

But then I re-read "John gets seasick" as "John gets seasick" ... so he was on the ship!

Which then means the single answer is:

Cindy Car

John Ship

Mr. Jones Train

Rachel Plane.

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**Bob****Administrator**- Registered: 2010-06-20
- Posts: 9,635

hi excelerator

Welcome to the forum.

It took me a while to track it down but I raised this issue early on in my MIF membership.

http://www.mathisfunforum.com/viewtopic.php?id=14426

The question is poorly worded as 'gets seasick' could have two very different meanings. On reflection, I like your version and it is more satisfying as it leads to a single answer.

Happy puzzling!

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Sometimes I deliberately make mistakes, just to test you! …………….Bob

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**imcute****Member**- Registered: 2022-09-28
- Posts: 176

enumeration

1=rachel 2=john 3=jones 4=cindy

train car plane ship

3 not on third place

4 not on second place

2 not on 4th place

1 2 3 4x

1 2 4 3

1 4 2 3x

1 4 3 2x

1 3 2 4

1 3 4 2x

2 1 3 4x

2 1 4 3

2 4 1 3x

2 4 3 1x

2 3 1 4

2 3 4 1

3 2 1 4

3 2 4 1

3 4 2 1x

3 4 1 2x

3 1 2 4

3 1 4 2x

4 1 3 2x

4 1 2 3

4 2 1 3

4 2 3 1x

4 3 1 2x

4 3 2 1

so there are 12 solutions

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