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## #1 2007-05-05 20:27:32

espeon
Real Member
Registered: 2006-02-05
Posts: 2,586

### A logic-Algebra problem...

Um on the main site on algebra problems on Logic 1 it says...

A^(C)=LOGIC

5^(7)=78125

That potentially is wrong? C is 5 and A has a 7 next to it? and techniquly C and L are the same...

Presenting the Prinny dance.
Take this dood! Huh doood!!! HUH DOOOOD!?!? DOOD HUH!!!!!! DOOOOOOOOOOOOOOOOOOOOOOOOOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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## #2 2007-05-06 03:54:41

Zach
Member
Registered: 2005-03-23
Posts: 2,075

### Re: A logic-Algebra problem...

According to the equation, A^C must equal L * O * G * I * C

So, if, according to you, C = 5, then A ^ 5 is equal to L * O * G * I * 5.

What do you mean by A has a 7 next to it?

Your question doesn't make the most sense really.

Boy let me tell you what:
I bet you didn't know it, but I'm a fiddle player too.
And if you'd care to take a dare, I'll make a bet with you.

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## #3 2007-05-06 11:00:01

MathsIsFun
Registered: 2005-01-21
Posts: 7,713

### Re: A logic-Algebra problem...

Ooops ... you may be right.

It should be C[sup]L[/sup] = LOGIC

5[sup]7[/sup] = 78125

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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## #4 2007-05-08 03:43:46

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

### Re: A logic-Algebra problem...

Here's a bit of a variant: C^(A) = LOGIC.

Why did the vector cross the road?
It wanted to be normal.

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