Math Is Fun Forum
You are not logged in.
- Topics: Active | Unanswered
Pages: 1
#1 2007-05-05 20:27:32
- espeon
- Real Member
- Registered: 2006-02-05
- Posts: 2,586
A logic-Algebra problem...
Um on the main site on algebra problems on Logic 1 it says...
A^(C)=LOGIC
5^(7)=78125
That potentially is wrong? C is 5 and A has a 7 next to it? and techniquly C and L are the same...
Presenting the Prinny dance.
Take this dood! Huh doood!!! HUH DOOOOD!?!? DOOD HUH!!!!!! DOOOOOOOOOOOOOOOOOOOOOOOOOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Offline
#2 2007-05-06 03:54:41
- Zach
- Member
- Registered: 2005-03-23
- Posts: 2,075
Re: A logic-Algebra problem...
According to the equation, A^C must equal L * O * G * I * C
So, if, according to you, C = 5, then A ^ 5 is equal to L * O * G * I * 5.
What do you mean by A has a 7 next to it?
Your question doesn't make the most sense really.
Boy let me tell you what:
I bet you didn't know it, but I'm a fiddle player too.
And if you'd care to take a dare, I'll make a bet with you.
Offline
#3 2007-05-06 11:00:01
- MathsIsFun
- Administrator
- Registered: 2005-01-21
- Posts: 7,713
Re: A logic-Algebra problem...
Ooops ... you may be right.
It should be C[sup]L[/sup] = LOGIC
5[sup]7[/sup] = 78125
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
Offline
#4 2007-05-08 03:43:46
- mathsyperson
- Moderator
- Registered: 2005-06-22
- Posts: 4,900
Re: A logic-Algebra problem...
Here's a bit of a variant: C^(A) = LOGIC.
Why did the vector cross the road?
It wanted to be normal.
Offline
Pages: 1