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I have discovered something amazing.
99*99=9801
999*999=998001
9999*9999=99980001
weird.
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Cool pattern!
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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so basicly.
for a number:
The Beginning Of All Things To End.
The End Of All Things To Come.
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Nice one.
Reminds me of 37.
37*3 = 111
37*6 = 222
37*9 = 333
37*12 = 444
37*15 = 555
37*18 = 666 (ACK!)
37*21 = 777
37*24 = 888
37*27 = 999
37*30 = 1110
37*33 = 1221
37*36 = 1332
37*39 = 1443
37*42 = 1554
37*45 = 1665
37*48 = 1776
37*51 = 1887
37*54 = 1998
37*57 = 2109
37*60 = 2220
...
And so on.
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Last edited by JaneFairfax (2007-05-06 23:54:03)
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I think I came up with a theorem to generalize all of these:
For any two numbers a and b, there exists a third number c such that a * b = c.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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wahahaha!
A logarithm is just a misspelled algorithm.
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You missed the first one!
9x9 = 81.
There's also a very similar pattern that happens with repeated 3s.
3x3 = (0)9
33x33 = 1089
333x333 = 110889
3333x3333 = 11108889
...
Why did the vector cross the road?
It wanted to be normal.
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An interesting finding! Here is the proof:
(10[sup]n[/sup]-1)²=10[sup]2n[/sup]-2*10[sup]n[/sup]+1
the first two elements add up to
9..980...0
the n zeros and the 8 are derived from substracting 2*10[sup]n[/sup], also the digits of this number are only 2n digits instead of 2n+1 digits. So there are totally 2n-n-1=n-1 9's in it.
To write the final result, just write n-1 9's and one 8 as the former n digits, then write n-1 0's and the last 1 for the latter n digits.
Last edited by George,Y (2007-05-11 19:16:25)
X'(y-Xβ)=0
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I like 37 ~lol
Numbers are the essence of the Universe
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I wonder if you might be interested in this index of arithmetical tricks:
http://mathforum.org/k12/mathtips/beatcalc.html
You might find your own in there
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errh...so many arithmetical tricks........
X'(y-Xβ)=0
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Man, that's too much work. I'm not too big on calculations like that. I hate when people are like "you're a mathematician? What is 47236 times 2923.424?" as if all math is just arithmetic. You don't need special mathematical insight to do such things. Dividing 13-digit numbers in your head isn't the same as being able to prove a theorem or understand a mathematical concept. Anyway I just wanted to say that. Have a nice day.
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I wonder if you might be interested in this index of arithmetical tricks:
http://mathforum.org/k12/mathtips/beatcalc.html
You might find your own in there
My God.
I shall now commence memorising.
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Anyway, learning those tricks is only volentary, isn't it??
X'(y-Xβ)=0
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Heh, the discovery is in there. Number 16. They've also got the one with 3s, and also patterns with repeating 1s and 6s.
1x1 = 1
11x11 = 121
111x111 = 12321
1111x1111 = 1234321
...
(This breaks down at 10 ones, because things start carrying)
Also,
6x6 = 36
66x66 = 4356
666x666 = 443556
6666x6666 = 44435556
...
Perhaps not very useful, but certainly interesting.
Why did the vector cross the road?
It wanted to be normal.
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I haven't checked to see if this one is in there, but check this out
11^0 = 1
11^1 = 11
11^2 = 121
11^3 = 1331
11^4 = 14641
Pascal's triangle! Or... at least that's what my math teacher told me... After 11^4 its gets a bit weird.
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That works because Pascal's Triangle tells you the coefficients of the expansion of (x+1)^n.
11^n is just the case when x=10.
It stops working at the 6th row because in the triangle it would be 1 5 10 10 5 1, but you can't have a 10 digit so things carry over instead.
1 5 10 10 5 1 becomes 1 5 11 0 5 1, which becomes 1 6 1 0 5 1.
Why did the vector cross the road?
It wanted to be normal.
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