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#1 2007-10-19 04:20:11

Dross
Member
Registered: 2006-08-24
Posts: 325

Two functions are walking down the street...

Two functions, x and e[sup]x[/sup], are walking down the street one day when they notice a differential operator walking towards them.

"Oh no," says x, "that's a big mean differential operator! If he catches me he'll differentiate me and then I'll just be a constant function!"

"Don't worry," says e[sup]x[/sup], "I'm my own derivative, so he won't change me if he tries to differentiate me - you go hide in that alley and I'll sort him out!"

After hiding in the alley, x peeks out to see what's happening, and watches as e[sup]x[/sup] approaches the differential operator.

"Hi there, I'm e[sup]x[/sup]" he says.

"Hi there," comes the reply, "I'm d/dy."

Last edited by Dross (2007-10-19 04:20:59)


Bad speling makes me [sic]

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#2 2007-10-19 04:26:32

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: Two functions are walking down the street...

Two strings walk into a bar.  One says to the bartender, "I'll have what ever is on tap."  The other says, "Give me a rum and coke^$&#IFJ#@*8238#&@*."  The first string then says, "Sorry.  He's not null terminating."


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#3 2007-10-20 14:37:08

JohnnyReinB
Member
Registered: 2007-10-08
Posts: 453

Re: Two functions are walking down the street...

Please explain the jokes pls. I don't get them very much. TY


"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted" wink

Nisi Quam Primum, Nequequam

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#4 2007-10-20 20:03:00

Identity
Member
Registered: 2007-04-18
Posts: 934

Re: Two functions are walking down the street...

In the first one, is not worried, because he thinks the operator will be d/dx, since

, and he won't be harmed. But the operator is d/dy, and

, if d/dy operates on him he is gone!!!

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#5 2007-10-20 21:39:46

elman
Member
Registered: 2007-10-18
Posts: 2

Re: Two functions are walking down the street...

Let epsilon be less than zero, and it was!

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