You are not logged in.
I just made a page on Polynomials - Long Multiplication
But ... does anyone know a better method when there is more than one variable? Other than "make up the columns as you go"?
How would YOU do (x[sup]2[/sup] + 2xz + z) (x + z) ?
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
Offline
I've never even heard of long multiplication. The only way I know how to do it is to multiply term by term then add common ones together:
(ax^2 + bx + c)(dx^2 + ex + f) = adx^4 + aex^3 + afx^2 + bdx^3 + bex^2 + bfx + cdx^2 + cex + cf
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
Offline
Personally, I would do it Vertically:
(x2 + 2xz + z) (x + z)=
x^2 + 2xz + z
x + z
________________________
x^2z +2xz^2+ z^2
x^3 +2x^2z + xz
____________________________
x^3 +3x^2z +2xz^2+ z^2 +xz
It would just be like Arithmetic Multiplication
"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted"
Nisi Quam Primum, Nequequam
Offline
It's just another way of setting things out I guess, and if you're better at it than normal expansion then that's great.
15 * 92 = 10(92)+5(92) = 920 + 460 = 1380
But personally I like normal expansion because you can do fancy tricks.
Offline
How would YOU do (x[sup]2[/sup] + 2xz + z) (x + z) ?
I'd multiply the like variables, and add the exponents, that would make things fairly easy! Moreover, multiplying a binomial of degree 2 wouldn't take much time.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
Offline