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This is a brilliant approximation for factorials, particularly, factorials of higher order numbers.
For example, 1000! as per this formula is 4.023537292 x 10^2567. The actual value as per the calculator in the scientific mode is 4.0238726 x 10^2567. :cool::cool:
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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sweetness!
A logarithm is just a misspelled algorithm.
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sweetness!
Very much so, if you think an error of
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I just like how it contains both pi and e.
A logarithm is just a misspelled algorithm.
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mikau wrote:sweetness!
Very much so, if you think an error of
is ok.
Which comes out to a relative error of 0.008%. I'll take that.
Wrap it in bacon
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mikau wrote:sweetness!
Very much so, if you think an error of
is ok.
EDIT: Aah post collison
Last edited by Daniel123 (2007-12-11 05:37:01)
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depends on what your priorities are i guess.
A logarithm is just a misspelled algorithm.
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This is a brilliant approximation for factorials, particularly, factorials of higher order numbers.
For example, 1000! as per this formula is 4.023537292 x 10^2567. The actual value as per the calculator in the scientific mode is 4.0238726 x 10^2567. :cool::cool:
So does this actually converge on the factorial value as n goes to infinity?
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well both n! and the approximation both diverge to infinity as n goes to infinity
The Beginning Of All Things To End.
The End Of All Things To Come.
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Yes.
http://en.wikipedia.org/wiki/Stirling%27s_approximation
Wrap it in bacon
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i think he meant, does
Last edited by mikau (2007-12-11 06:36:33)
A logarithm is just a misspelled algorithm.
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I agree that percentage difference is more important than absolute difference.
If you consider the absolute argument the other way, you could say that 10mg of poison on your food is only 10mg more than the recommended amount and so not worth worrying about.
On the same theme, I would guess that this is false:
, but this is true:
Why did the vector cross the road?
It wanted to be normal.
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isnt that identical? the only time that that would converge to 1, is if the first converged to 0?
The Beginning Of All Things To End.
The End Of All Things To Come.
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Because the error may grow, but not as fast as n! grows.
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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yeah. Note
Last edited by mikau (2007-12-11 13:20:49)
A logarithm is just a misspelled algorithm.
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What additional requirement can we impose so that Luca's statement holds?
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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Equality? That is, instead of
just getting arbitrarily close to 1, it actually has to get there.Why did the vector cross the road?
It wanted to be normal.
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Certainly you can come up with a restriction far less restricting than that. Remember, this restriction can't apply to Mikau's example.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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if the two limits each converge to the same finite number?
Last edited by mikau (2007-12-12 05:08:17)
A logarithm is just a misspelled algorithm.
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Bingo.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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It is also possible for the absolute error to approach 0 while the limits themselves diverge to infinity. As a trivial example, let f(x) = x^2 and g(x) = x^2 + 1/x. Then
Last edited by TheDude (2007-12-12 08:09:28)
Wrap it in bacon
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Bingo.
awesome! But are there any other restrictions that would do it?
A logarithm is just a misspelled algorithm.
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