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#1 2008-01-05 19:41:56
- esatpllana
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- Registered: 2007-11-22
- Posts: 12
fractions by me
hi all!
sometimes when we want I don't know how to say in english i think
we have to find 2\3 of 9 we know that is 6 but also we can multi ply 2 and 3 and to be 6
another example.
Problem 1.
In the class we have 16 girls and are 4\7 of class. How many male have tha class.
Answer.
mutiply 4 and 7 = 28, 28 - 16 = 12
so class have 12 boys.
math answer.
continue to you see youu
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Mitrovica My City
tenth a class
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#2 2008-01-06 05:53:19
- MasterofDisguise
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Re: fractions by me
wow
(im an ALIEN 
) im kool 
(WHAT 
You cant steal my fridge!)]
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#3 2008-01-06 14:21:29
- John E. Franklin
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- Registered: 2005-08-29
- Posts: 3,588
Re: fractions by me
Excellent. I agree.
You are doing fractions perfectly!!
igloo myrtilles fourmis
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#4 2008-01-06 19:21:58
- esatpllana
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- Registered: 2007-11-22
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Re: fractions by me
thanks to all
live your day
Mitrovica My City
tenth a class
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#5 2008-01-07 09:04:31
- MasterofDisguise
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Re: fractions by me
your welcome and you deserve it
(im an ALIEN ) im kool (WHAT You cant steal my fridge!)]
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#6 2008-01-12 19:09:10
- esatpllana
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- Registered: 2007-11-22
- Posts: 12
Re: fractions by me
can we invent any formula for this hehe ciao
live your day
Mitrovica My City
tenth a class
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#7 2008-01-14 18:10:20
- John E. Franklin
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Re: fractions by me
Girls = 16 = G
Easier Fraction By 4 = n = 4
Fraction of class Girls = 4/7 = (G/n)/7 --> (G/n)/(28/n) --> G/28
Boys = 28 - G ---> 28 - 16 ---> 12 boys.
Notice that both boys and girls can each be divided evenly by 4 to make the easy fraction 4/7 and 3/7.
...also 28/28 = 1, and so 28/28 - G/28 = Boys/28
28/28 means the whole class.
Last edited by John E. Franklin (2008-01-14 18:13:03)
igloo myrtilles fourmis
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#8 2008-01-19 00:59:14
- Khushboo
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- Registered: 2007-10-16
- Posts: 47
Re: fractions by me
Hi Esat Pllana
Good way to approach the word problems. In fact expressing fractions using figures or shapes generally lends clarity to the problem. I have another way of doing the above problem. Express 4/7 parts in terms of figure, the way you have expressed. Now instead of multiplying 4 and 7, distribute fairly and equally 16 objects in the 4/7 parts of the circle. Each part i.e. 1/7 parts in 4/7 parts will comprise of 4 objects . Now if we are dividing the circle equally into 7 parts we are also assuming that each part will comprise of equal number of objects or headcounts. Hence in the unshaded part that is 3/7th part, each part will comprise of 4 objects, hence a total of 12 objects of boy headcount.
I think it is possible, however not so sure.
Regards
Khushboo
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#9 2008-01-19 09:30:17
- esatpllana
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- Registered: 2007-11-22
- Posts: 12
Re: fractions by me
thanks for this
live your day
Mitrovica My City
tenth a class
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