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Looks like y = x is tangential to each of the little arches. I can't be bothered to check this analytically.
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Plot the graph, alongside its negative, in polar coordinates with as many revolutions as you can, and zoom out
Last edited by Daniel123 (2008-06-11 02:54:28)
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so y = x crosses your graph at x = 2kpi, and at each of these points, the gradient of your curve is 1, so y = x is a tangent to the curve on each of its sections
The Beginning Of All Things To End.
The End Of All Things To Come.
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by wrapping the cosine in absolute value, you can make the graph continuous!
ln(abs((cos(x))/(e^(-x))))
A logarithm is just a misspelled algorithm.
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Is the y value undefined in the gaps? Just wondering.
(I'm not analyzing details, but just wondered if it was the ln of a negative number)
igloo myrtilles fourmis
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It is john, the undefined areas of the graph are when cos(x) <= 0
the equation of the his graph can be rearranged more simply as x + ln(cos x)
The Beginning Of All Things To End.
The End Of All Things To Come.
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You spelled weird incorrectly.
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You spelled weird incorrectly.
'twas a typing mistake. I can spel.
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Picky picky, Jane!
Anyway, it is fun to replace x in many functions with b*sin(a*x), as it must result in a repeating pattern.
Try graphing sin(pi*sin(x)) for instance!
A logarithm is just a misspelled algorithm.
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