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(A, B, C) € R
A + B + C = 5
AB + BC + CA = 0
ABC = -11
How to find A, B, C?
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mmm... actually what i real was trying to do was the same thing!
Means..
I was trying to solve the cubic equation x^3+5x-11=0.
I wrote x^3+5x-11=(x-a)(x-b)(x-c)=0
upon equating the coefficients i get the above system of equations which i really can't solve...
Any suggestions or ways?
If two or more thoughts intersect, there has to be a point!
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Im afraid that cubic equation doesnt have nice solutions. But you can still solve it in closed form, e.g. by Cardanos method. Trouble is, the working may be very very tedious, and the answers may be totally horrible-looking.
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